Winappdriver: how to get the window handle of an application which is currently running.

Created on 11 Apr 2019 · 4Comments · Source: microsoft/WinAppDriver

I need to get the window-handle (example "0xB0F4C") of an application(process) by looping through all the process that is currently open in Inspect window. This window handle will then be used to create a new session in winappdriver like this: capabilities.setCapability("appTopLevelWindow", "0xB0F4C");

Please suggest how to get the window handle.

issue

Source

RajneeshK2018

Most helpful comment

Create a root session and find the Window by it's properties from there.
I can see that it has "Name" attribute set to "Qualtia Setup".

naeemakram on 12 Apr 2019

👍3

All 4 comments

Create a root session and find the Window by it's properties from there.
I can see that it has "Name" attribute set to "Qualtia Setup".

naeemakram on 12 Apr 2019

👍3

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Automated UI Testing Windows Apps in Appium WinAppDriver, C#

naeemakram on 11 Oct 2019

@naeemakram I am facing an error on the remote machine. Failed to locate opened application window with appId: ApplicationID_bpx612tnafn9m!App, and processId: 4932.