Ypimagepicker: Get selected image physical url for sending to server?!?!?!?

Created on 28 Aug 2018 · 3Comments · Source: Yummypets/YPImagePicker

how to get selected image's physical url for sending to server?!?!?!?

Source

rajabpour

Most helpful comment

@rajabpour, as explained by @gintechsystems you should only need the Data to send the image to the server as follows :

let picker = YPImagePicker()
picker.didFinishPicking { [unowned picker] items, _ in
    if let photo = items.singlePhoto {
        print(photo.image) // Final image selected by the user (UIIMage)
        let imageData = UIImageJPEGRepresentation(photo.image, 1)
        // Typically send imageData to server with a multipart request
    }
    picker.dismiss(animated: true, completion: nil)
}
present(picker, animated: true, completion: nil)

Hope this helps :)

s4cha on 29 Sep 2018

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All 3 comments

You don't need the url just get the data.

gintechsystems on 26 Sep 2018

👍1

@rajabpour, as explained by @gintechsystems you should only need the Data to send the image to the server as follows :

let picker = YPImagePicker()
picker.didFinishPicking { [unowned picker] items, _ in
    if let photo = items.singlePhoto {
        print(photo.image) // Final image selected by the user (UIIMage)
        let imageData = UIImageJPEGRepresentation(photo.image, 1)
        // Typically send imageData to server with a multipart request
    }
    picker.dismiss(animated: true, completion: nil)
}
present(picker, animated: true, completion: nil)

Hope this helps :)

s4cha on 29 Sep 2018

❤1 👍1

@s4cha great example. What are you adding in the next version related to this?

gintechsystems on 30 Sep 2018

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