Typescript: 2339 Property 'style' does not exist on type 'Element'.

Created on 25 May 2015  ·  23Comments  ·  Source: microsoft/TypeScript

Some example of code:

class Test {
  constructor(elem:Element) {
    elem.style.color = 'red';
  };
}

let elem = document.querySelector('#test');
let test = new Test(elem);

This produces:
2339 Property 'style' does not exist on type 'Element'.
If I change elem:Element to elem:HTMLElement then is says:
2345 Argument of type 'Element' is not assignable to parameter of type 'HTMLElement'. Property 'accessKey' is missing in type 'Element'.

I understand what querySelector might not always return HTML or SVG elements, but why Element does not have style property?

Question

Most helpful comment

I am not the best one to answer the question about the DOM sepec. We do generate these from IE's definitions. it is possible that it is an issue. @zhengbli would be able to comment better here.

For your issue, i believe you need to use HTMLElement all the time; so assuming you do not use any SVG elements in this code path, casting should be safe.

class Test {
  constructor(elem:HTMLElement) {
    elem.style.color = 'red';
  };
}

let elem = <HTMLElement>document.querySelector('#test');
let test = new Test(elem);

All 23 comments

I am not the best one to answer the question about the DOM sepec. We do generate these from IE's definitions. it is possible that it is an issue. @zhengbli would be able to comment better here.

For your issue, i believe you need to use HTMLElement all the time; so assuming you do not use any SVG elements in this code path, casting should be safe.

class Test {
  constructor(elem:HTMLElement) {
    elem.style.color = 'red';
  };
}

let elem = <HTMLElement>document.querySelector('#test');
let test = new Test(elem);

@mhegazy yes, I now how to work around it right now, I was just confused what Element does not have style property. I am also not sure if it should have it, but it will be strange in a future to always cast any DOM requests (querySelector, getElementById, etc) to HTMLElement.

According to the MDN spec, Element interface doesn't have a style property, and querySelector does return Element.
However, in the case of getElementById, we made it convenient by returning HTMLElement by default, although it is different from the spec. I don't know if we should do the same thing for other methods that don't obviously return HTMLElement over Element in most of the time, as it does feel hacky and inconsistent.

I am not saying MDN is wrong, I am pretty sure they are right, but they also say what Element have Element.onwheel :-)

that don't obviously return HTMLElement over Element in most of the time, as it does feel hacky and inconsistent.

Same for getElementById, it does not returns HTMLElement more often than, for example, querySelector because one can easily request inline SVG element by id.

I do not think svg or xml elements are more frequint for querySelector, but I can agree what for XPath that might not be true.
So, since querySelector returns Element then any developer should cast it to type they wanted (HTML, SVG, something else?). It would be good to have HTMLElement as a default for such methods, since (as far as I know :-)) HTML is default for the web (ignore xhtml here).

DOM Level 3 IDL for Element does not contain it.

@kitsonk yes, I got it. Please treat now this issue as "Return HTMLElement by default instead of Element from dom request methods (getElement(s)By*, querySelector(All), etc)"

@NekR while i agree that an HTMLElement is more common target for querySelector/querySelectorAll, this change leaves users of SVGElements with one extra cast:

// with the current definition
querySelector(selectors: string): Element;

// this is how you access it
let htmlElement  = <HTMLElement>document.querySelector('#test');
let svgElement = <SVGElement>document.querySelector('#test');

// if it was changes to HTMLElement
querySelector(selectors: string): HTMLElement;

// this is how you access it
let htmlElement = document.querySelector('#test');
let svgElement = <SVGElement><Element>document.querySelector('#test');

That is a breaking change though, as it will break existing calls that expect to cast to SVGElement.

As I suggested in issue 424, querySelector/querySelectorAll etc. can return UniversalElement by default, which is an imaginary Element that extends all known sub-interfaces of Element. Thus no casts are ever needed, no matter for HTML or SVG.

Of cause this is not quite conformant to WebIDL of DOM specs, but I don't think there are many TS users that care about this problem.

Indeed, double casting seems weird. But it's also strange that TypeScript follows spec more than real use cases. What is a real benefit of returning Element for such methods except of being type-compatible with spec?

UniversalElement solution seems good. I do not know if it's possible, but something like that will help.

SVG elements really do exist.

If your JS runs over arbitrary DOM trees, it might encounter one, and we'd be wrong to act as if that were not the case.

Use a type guard. You need to check for null anyway.

let elem = querySelector("#test")
if (elem instanceof HTMLElement) {
    // elem.style
} else {
    throw new Error("element #test not in document")
}

SVG elements DO have 'style' property in browsers (including MS IE11 and Edge), so usually you don't have to check for its existence.

The exception is arbitrary XML elements, including MathML in Firefox ( Safari not tested ). MathML is dying and most web developers don't mix arbitrary XML in HTML, so this is not a problem in practice.

According to the CSSOM spec, both HTMLElement and SVGElement have style propterty (Element doesn't, however). So I suggest adding style to SVGElement, and to Element as an optional property in TS. can we reopen this issue?

If someone are still looking for the solution, I can suggest do the following simple solution. Becasue HTMLElement was extended from Element, so if we queried from the DOM, it's absolutely a HTMLElement, we can cast from Element to HTMLElement by using:

(document.querySelector('ion-nav') as HTMLElement).style.color = 'red';

Hope this help :)

@quangpdt
I have a bug:
Type 'Element' is not assignable to type 'HTMLElement'.Property 'accessKey' is missing in type 'Element'.
In:
/** @type {HTMLElement} */ const enSentenceEl = /** @type {HTMLElement} */ sentenceEl.querySelector(".enSentence");

How it's possible?
After all, HTMLElement inherits from Element.

When I do this:
const enSentenceEl = /** @type {HTMLElement} */ sentenceEl.querySelector(".enSentence");
Element type simply does not change. Still only: Element.

I needed only the first element so i used let elem = document.querySelector('#test')[0] instead. in your case you can loop over the array and apply the style.

when you know I specific ID in your HTML corresponds to a more specialized type than that returned by the DOM APIs I find the following pattern to be very useful and that it satisfies the typechecker while making the code more self documenting

declare global {
  interface Document {
    querySelector(s: '#test'): NodeList<Element & Extras>;
  }
}

@look997 Use type assertion:

as HTMLElement

I don't think that comment can change type.

@devcer querySelector returns one element, not array https://developer.mozilla.org/en-US/docs/Web/API/Document/querySelector

@kaziupir

@look997 Use type assertion:

W pliku JavaScript? Tam chyba się nie da tak?
Ja to mam w pliku js.

@look997 A to nie wiem, nigdy typescriptu nie używałem w pliku js. Może po prostu przejdź na używanie plików .ts. https://www.typescriptlang.org/docs/handbook/migrating-from-javascript.html

Hi!
I have same problem with svg func:
image

And I did next:

interface SVGElementEx extends SVGElement {
    getTotalLength(): number;
}

How true this desision?

@Dok11 you can add that property to existing interface, i.e. just remove SVGElementEx extends.

@NekR how will I change existing interface? You talk about file \lib.es6.d.ts?
Can you show simple example?

Sample in whatever place:

interface SVGElement {
    getTotalLength(): number;
}
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