Indeed a good proposal.

However what about the following examples, which are valid overrides to me:

class Snake extends Animal {
    override move(meters:number, height=-1):void {
    }
}

class A {...}
class Animal {
    setA(a: A): void {...}
    getA(): A {...}
}

class B extends A {...}
class Snake extends Animal {
    override setA(a: B): void {...}
    override getA(): B {...}
}

Additionally I would add a compiler flag to force the override keyword to be present (or reported as a warning).
The reason is to catch when renaming a method in a base class that inherited classes already implement (but not supposed to be an override).

stephanedr on 10 Feb 2015

👍20

Ah nice examples. Generally speaking I would expect the use of the override keyword to enforce _exact_ matching of signatures, as the goal of using it is to maintain a strict typed class hierarchy. So to address your examples:

Adding an additional default param. This would generate a compile error: Snake super does not define move(meters:number):void. While the derived method is functionally consistent, client code calling Animal.move may not expect derived classes to also be factoring in height (as the base API does not expose it).
This would (and should always) generate a compile error, as it is not functionally consistent. Consider the following addition to the example:

class C extends A {...}
var animal : Animal = new Snake();
animal.setA(new C());
// This will have undefined run-time behavior, as C will be interpreted as type B in Snake.setA

So example (2.) is actually a great demo of how an override keyword can catch subtle edge cases at compile time that would otherwise be missed! :)

And I would again stress that both examples may be valid in specific controlled/advanced javascript scenarios that may be required... in this case users can just choose to omit the override keyword.

rwyborn on 10 Feb 2015

👍5

This will be useful. We currently work around this by including a dummy reference to the super method:

class Snake extends Animal {
    move(meters:number, height?:number):void {
         super.move; // override fix
    }
}

But this only guards against the second case: super methods being renamed. Changes in signature do not trigger a compilation error. Furthermore, this is clearly a hack.

I also don't think that default and optional parameters in the derived class method's signature should trigger a compilation error. That may be correct but goes against the inherent flexibility of JavaScript.

NoelAbrahams on 11 Feb 2015

😄5

@rwyborn
It seems we don't expect the same behaviour.
You would use this override keyword to ensure a same signature, whereas I would use it more as a readibiliy option (so my request to add a compiler option to force its usage).
In fact what I would really expect is that TS detects invalid overriding methods (even without the use of override).
Typically:

class Snake extends Animal {
    move(meters:number, height:number):void {}
}

should raise an error, because it's really an override of Animal.move() (JS behaviour), but an incompatible one (because height is not supposed to be optional, whereas it will be undefined if called from an Animal "reference").
In fact using override would only confirm (by the compiler) that this method really exists in the base class (and so with a compliant signature, but due to the previous point, not due to the override keyword).

stephanedr on 11 Feb 2015

@stephanedr , speaking as a single user I actually agree with you that the compiler should just always confirm the signature, as I personally like to enforce strict typing within my class hierarchies (even if javascript doesn't!!).

However in proposing that this behavior is optional via the override keyword I am trying to keep in mind that ultimately javascript is untyped, and hence enforcing the strict signature matching by default would result in some javascript design patterns no longer being expressible in Typescript.

rwyborn on 11 Feb 2015

@rwyborn I'm glad you mentioned the C++ implementation because that's exactly how I imagined it should work before I got here - optionally. Although, a compiler flag that forced the use of the override keyword would go down well in my book.

The keyword would allow compile time errors for a developers clumsy typing, which is what worries me most about overrides in their current form.

class Base {
    protected commitState() : void {

    }
}


class Implementation extends Base {
    override protected comitState() : void {   /// error - 'comitState' doesn't exist on base type

    }
}

Currently (as of 1.4) the Implementation class above would just declare a new method and the developer would be none the wiser until they notice their code isn't working.

kungfusheep on 14 Mar 2015

👍7

Discussed at suggestion review.

We definitely understand the use cases here. The problem is that adding it at this stage in the language adds more confusion than it removes. A class with 5 methods, of which 3 are marked override, wouldn't imply that the other 2 _aren't_ overrides. To justify its existence, the modifier would really need to divide the world more cleanly than that.

RyanCavanaugh on 5 May 2015

👎2 👍2

Please excuse the whining, but honestly, while your argument does apply to the public keyword in a language where everything is public by default, quite world dividing indeed, having things like abstract and an optional override keyword will simply help developers feel safer, make less mistakes and waste less time.

Overriding is one of the few remaining highly-typo-sensitive aspects of the language, because a mistyped overriding method name is not an obvious compile time problem. The benefit of override is obvious, as it you allows you to state your intention to override - if the base method doesn't exist its a compile time error. All hail the type system. Why would anyone not want this?

hdachev on 5 May 2015

👍70 🎉12 👀3 🚀3 ❤3

I concur 100% with @hdachev , the small inconsistency referred too by @RyanCavanaugh is easily out weighed by the benefits of the keyword in bringing compile time checks to method overrides. I would again point out that C++ uses an optional override keyword successfully in exactly the same way as suggested for typescript.

I can not emphasize enough how much of a difference override checking makes in a large scale code base with complex OO trees.

Finally I would add that if the inconsistency of an optional keyword really is a concern, then the C# approach could be used, that is the mandatory use of either the "new" or "override" keywords:

class Dervied extends Base {

    new FuncA(newParam) {} // "new" says that I am implementing a new version of FuncA() with a different signature to the base class version

    override FuncB() {} // "override" says that I am implementing exactly the same signature as the base class version

    FuncC() {} // If FuncC exists in the base class then this is a compile error. I must either use the override keyword (I am matching the signature) or the new keyword (I am changing the signature)
}

rwyborn on 5 May 2015

👍16 👀2 😕1

This isn't analogous to public because a property without an access modifier is known to be public; a method without override is _not_ known to be non-override.

Here's a runtime-checked solution using decorators (coming in TS1.5) that produces good error messages with very little overhead:

/* Put this in a helper library somewhere */
function override(container, key, other1) {
    var baseType = Object.getPrototypeOf(container);
    if(typeof baseType[key] !== 'function') {
        throw new Error('Method ' + key + ' of ' + container.constructor.name + ' does not override any base class method');
    }
}

/* User code */
class Base {
    public baseMethod() {
        console.log('Base says hello');
    }
}

class Derived extends Base {
    // Works
    @override
    public baseMethod() {
        console.log('Derived says hello');
    }

    // Causes exception
    @override
    public notAnOverride() {
        console.log('hello world');
    }
}

Running this code produces an error:

Error: Method notAnOverride of Derived does not override any base class method

Since this code runs at class initialization time, you don't even need unit tests specific to the methods in question; the error will happen as soon as your code loads. You can also sub in a "fast" version of override that doesn't do any checking for production deployments.

RyanCavanaugh on 5 May 2015

👍8

@RyanCavanaugh So we are at Typescript 1.6 and decorators are still an experimental feature, not something I want to deploy in a large scale production codebase as a hack to get override working.

To try yet another angle, every popular typed language out there supports the "override" keyword; Swift, ActionScript, C#, C++ and F# to name a few. All these languages share the minor issues you have expressed in this thread about override, but clearly there is a large group out there who see that the benefits of override far out weigh these minor issues.

Are your objections purely based on cost/benefit? If I was to actually go ahead and implement this in a PR would it be accepted?

rwyborn on 1 Oct 2015

👍8

It's not just a cost/benefit issue. As Ryan explained, the issue is that marking a method as an override doesn't imply that another method _isn't_ an override. The only way that it would make sense is if all overrides needed to be marked with an override keyword (which if we mandated, would be a breaking change).

DanielRosenwasser on 1 Oct 2015

👎2

@DanielRosenwasser As outlined above, in C++ the override keyword is optional (exactly as proposed for Typescript) yet everyone uses it no problem and it is hugely useful on large code bases. Furthermore in Typescript is actually makes a lot of sense for it to be optional because of javascript function overloading.

class Base {
    method(param: number): void { }
}

class DerivedA extends Base {
    // I want to *exactly* implement method with the same signature
    override method(param: number): void {}
}

class DerivedB extends Base {
    // I want to implement method, but support an extended signature
    method(param: number, extraParam: any): void {}
}

As for the whole "doesn't imply that another method isn't an override" argument, It is exactly analogous to "private". You can write an entire codebase without ever using the private keyword. Some of the variables in that codebase will only ever be accessed privately and everything will compile and work fine. However "private" is some extra syntactic sugar you can use to tell the compiler "No really, compile error if someone tries to access this". In the same way "overload" is extra syntactic sugar to tell the compiler "I want this to exactly match the base class declaration. If it doesn't compile error".

rwyborn on 1 Oct 2015

👍22

You know what, I think you guys are fixated on the literal interpretation of "override". Really what it is marking up is "exactly_match_signature_of_superclass_method", but thats not quite as readable :)

class DerivedA extends Base {
    exactly_match_signature_of_superclass_method method(param: number): void {}
}

rwyborn on 1 Oct 2015

👍8

I too would like to have the override keyword available, and have the compiler generate an error if the method marked for override doesn't exist, or has a different signature, in the base class. It would help readability and for refactoring

jkristia on 13 Nov 2015

👍8

+1, also the tooling will get much better. My use case is using react. I've to check the definiton every time I'm using the ComponentLifecycle methods:

``` C#
interface ComponentLifecycle {
componentWillMount?(): void;
componentDidMount?(): void;
componentWillReceiveProps?(nextProps: P, nextContext: any): void;
shouldComponentUpdate?(nextProps: P, nextState: S, nextContext: any): boolean;
componentWillUpdate?(nextProps: P, nextState: S, nextContext: any): void;
componentDidUpdate?(prevProps: P, prevState: S, prevContext: any): void;
componentWillUnmount?(): void;
}

With override, or other equivalent solution,you'll get a nice auto-completion. 

One problem however is that I will need to override interface methods...

``` C#
export default class MyControlextends React.Component<{},[}> {
    override /*I want intellisense here*/ componentWillUpdate(nextProps, nextState, nextContext): void {

    }
}

olmobrutall on 12 Dec 2015

👍1

@olmobrutall it seems like your use case is better solved by the language service offering refactorings like "implement interface" or offering better completion, not by adding a new keyword to the language.

RyanCavanaugh on 14 Dec 2015

👎2

Lets not get distracted thou :) Language service features are only a small part of maintaining interface hierarchies in a large code base. By far and away the biggest win is actually getting compile time errors when a class way down in your hierarchy somewhere does not conform. This is why C++ added an optional override keyword (non-breaking change). This is why Typescript should do the same.

Microsoft's documentation for C++ override sums things up nicely, https://msdn.microsoft.com/en-us/library/jj678987.aspx

Use override to help prevent inadvertent inheritance behavior in your code. The following example shows where, without using override, the member function behavior of the derived class may not have been intended. The compiler doesn't emit any errors for this code.
...
When you use override, the compiler generates errors instead of silently creating new member functions.

rwyborn on 14 Dec 2015

👍13

By far and away the biggest win is actually getting compile time errors when a class way down in your hierarchy somewhere does not conform.

I have to agree. One pitfall that crops up in our teams is people thinking they've overridden methods when in fact they've slightly mis-typed or extended the wrong class.

Interface changes in a base library when working across many projects is harder than it should be in a language with an agenda like TypeScript.

We have so much great stuff, but then there are oddities like this and no class-level const properties.

kungfusheep on 14 Dec 2015

👍11

@RyanCavanaugh true, but the language service could be triggered after writing override, as many languages do, without the keyword is much harder to figure out when is the right moment.

About implement interface, note that most of the methods in the interface are optional and you're meant to override only the few ones you need, not the whole package. You could open a dialog with check boxes but still...

And while my current pain point is to find the name of the method, in the future will be great to get notified with compile-time errors if someone renames or changes the signature of a base method.

Couldn't the inconsitency be solve just by adding a warning when you don't write override? I think typescript is doing the right thing adding small reasonable breaking changes instead of preserving bad decisions for the end of time.

Also abstract is already there, they will make an awesome couple :)

olmobrutall on 15 Dec 2015

👍3

I felt the need for an 'override' specifier, too. In medium to large projects, this feature becomes essential and with all due respect I hope the Typescript team will reconsider the decision to decline this suggestion.

armandn on 4 Mar 2016

👍18

For anyone interested we've written a custom tslint rule that provides the same functionality as the override keyword by using a decorator, similar to Ryan's suggestion above but checked at compile-time. We'll be open-sourcing it soon, I'll post back when it's available.

kungfusheep on 4 Mar 2016

👍1

I strongly felt necessity of 'override' keyword, too.
In my case, I changed some of method name in a base class and I forgot to rename some of names of overriding methods. Of course, this leads some of bugs.

But, If there was such a feature, we can find these class methods easily.

As @RyanCavanaugh mentioned, if this keyword is just a optional keyword, this feature makes confusion. So, how about to make something flag in tsc to enable this feature?

Please reconsider this feature again....

kyasbal-1994 on 11 Mar 2016

👍7

To me, if the override keyword is to be useful, it needs to be enforced, like it is in C#. If you specify a method in C# that overrides the signature of a base method, you _must_ label it either override or new.

C++ is annoying and inferior compared to C# in some places because it makes too many keywords optional, and therefore precludes _consistency_. For example, if you overload a virtual method, the overloaded method can be marked virtual or not - either way it will be virtual. I prefer the latter because it aids other developers who read the code, but I can't get the compiler to enforce it being put in, which means our code-base will undoubtedly have missing virtual keywords where they should really be. The override keyword is similarly optional. Both are crap in my opinion. What is overlooked here is that code can serve as documentation and improve maintainability by enforcing the need for keywords rather than a "take it or leave it" approach. The "throw" keyword in C++ is similar.

To achieve the above objective in TypeScript, the compiler needs a flag to "enable" this stringent behaviour or not.

Insofar as the function signatures of the base and the override are concerned, they should be identical. But it would be desirable to allow covariance in the specification of the return type to enforce a compile-time check.

kevmeister68 on 17 Mar 2016

👍5

I'm coming to TS from AS3 so of course, I'm going to throw my vote here for an override keyword as well. To a developer who's new to any given codebase, seeing an override is a huge clue as to what might be going on in a (child) class. I think such a keyword hugely adds value. I would opt to make it mandatory, but I can see how that would be a breaking change and so should be optional. I really don't see a problem with the ambiguity that imposes, though I am sensitive to the difference between an optional override and the default public keyword.

TomAuger on 23 Mar 2016

👍6 ❤2

For all the +1ers -- can you talk about what's not sufficient about the decorator solution shown above?

RyanCavanaugh on 23 Mar 2016

To me it feels like an artificial construct, not a property of the language itself. And I guess that's by design, because that's what it is. Which I guess sends developer (well, me anyway) the message that it's transient, not a best practice.

obviously every language has its own paradigm and, being new to TypeScript I'm slow with the paradigm shift. I have to say though that override DOES feel like a best practice to me for a number of reasons. I'm making the switch to TypeScript because I have fully swallowed the strongly-typed koolaid, and believe that the cost (in terms of keystrokes and learning curve) is heavily outweighed by the benefits both to error-free code and code comprehension. override is a very important piece of that puzzle, and communicates some very important information about the role of the overriding method.

For me it's less about IDE convenience, though that is undeniably awesome when properly supported, and more about fulfilling what I believe to be the principles upon which you've built this language.

TomAuger on 23 Mar 2016

👍5

@RyanCavanaugh some issues that I see:

The decorator syntax will be harder for IDEs to provide code completion (yeah, I guess it could be done but they would need prior knowledge)
The derived class could change the visibility of a method - which in strict terms shouldn't be allowed
Difficult for the decorator to check the argument list and types, and compatible return type

joewood on 23 Mar 2016

👍3

The compiler is already checking the argument list and return type, though. And I think even if override did exist as a first-class keyword, we wouldn't enforce some new rule about signature identicalness

RyanCavanaugh on 23 Mar 2016

And I think even if override did exist as a first-class keyword, we wouldn't enforce some new rule about signature identicalness.

@RyanCavanaugh then I think you might be on a different page about the intent of the keyword. The whole point of it is for cases where you _want_ to enforce signature identicalness. This is for the design pattern where you have a deep complex hierarchy sitting on a base class that defines a contract of interface methods, and all classes in the hierarchy must _exactly_ match those signatures. By adding the override keyword on these methods in all the derived classes, you are alerted to any cases where the signature diverges from the contract set out in the base class.

As I keep saying this is not some esoteric use case. When working on a large code bases (with say hundreds or thousands of classes) this is an _every day_ occurrence, ie someone needs to change the signature of the base class (modify the contract), and you want the compiler to alert you to any cases throughout the hierarchy that no longer match.

rwyborn on 23 Mar 2016

👍4

The compiler will already warn of illegal overrides. The issue with the
current implementation is the lack of intent when declaring an overridden
method.

The decorator mentioned before just seems to go against what the language
is trying to achieve. There shouldn't be a runtime cost incurred for
something that can be dealt with at compile time, however small the cost.
We want to catch as much stuff going wrong as possible, without needing to
run the code to find out.

It's possible to achieve using the decorator and custom a custom tslint
rule, but would be better for the tooling ecosystem and the community for
the language to have an official keyword.

I think being optional is one approach, but as with with some C++ compilers
there are flags you can set which enforce its use (e.g. suggest-override,
inconsistent-missing-override). This would seem the best approach to avoid
breaking changes and seems consistent with other new features being added
recently such as nullable types and decorators.

On Wed, 23 Mar 2016 at 21:31, Rowan Wyborn [email protected] wrote:

And I think even if override did exist as a first-class keyword, we
wouldn't enforce some new rule about signature identicalness.

@RyanCavanaugh https://github.com/RyanCavanaugh then I think you might
be on a different page about the intent of the keyword. The whole point of
it is for cases where you _want_ to enforce signature identicalness. This
is for the design pattern where you have a deep complex hierarchy sitting
on a base class that defines a contract of interface methods, and all
classes in the hierarchy must _exactly_ match those signatures. By adding
the override keyword on these methods in all the derived classes, you are
alerted to any cases where the signature diverges from the contract set out
in the base class.

As I keep saying this is not some esoteric use case. When working on a
large code bases (with say hundreds or thousands of classes) this is an _every
day_ occurrence, ie someone needs to change the signature of the base
class (modify the contract), and you want the compiler to alert you to any
cases throughout the hierarchy that no longer match.

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kungfusheep on 23 Mar 2016

👍3

@kungfusheep fwiw the compiler only catches a certain class of illegal overrides, that is where there is a direct clash between declared params. It does _not_ catch the addition or removal of params, nor does it catch return type changes. These extra checks are what any override keyword would switch on.

rwyborn on 23 Mar 2016

The compiler correctly warns you if you _add_ a parameter to an overriding function.

Removing a parameter, though, is _totally valid_:

class BaseEventHandler {
  handleEvent(e: EventArgs, timestamp: number) { }
}

class DerivedEventHandler extends BaseEventHandler {
  handleEvent(e: EventArgs) {
    // I don't need timestamp, it's OK
  }
}

Changing the return type is also _totally valid_:

class Base {
  specialClone(): Base { ... }
}
class Derived extends Base {
  specialClone(): Derived { ... }
}

RyanCavanaugh on 24 Mar 2016

@RyanCavanaugh yes they are valid from a strict language perspective, but this is why I started using the term "contract" above. If a base class lays out a specific signature, when I use override I am stating that I want my derived class to strictly follow that signature. If the base class adds additional params or changes return type, I want to know every point in my code base that no longer matches, as the contract they were originally written against has now changed in some way.

The idea of having a big class hierarchy each with its own slightly different permutations of the base methods (even if they are valid from a language perspective) is nightmare inducing and takes me back to the bad old days of javascript before typescript came along :)

rwyborn on 24 Mar 2016

If the optionality is the main problem with the keyword, then why not make it mandatory when the base class method is defined as abstract? This way, if you wanted to enforce the pattern strictly you could simply add an abstract base class. To avoid breaking code a compiler switch could disable the check.

joewood on 24 Mar 2016

We seem to be talking about two different sets of expectations now. There's the missing-override/illegal override situation and then there's the explicit signature one. Can we all agree the former is the absolute bare-minimum we'd expect from this keyword?

I only say this because there are other ways of enforcing explicit method signatures currently, such as interfaces, but there is currently no way of explicitly stating the intent to override.

Ok, there is no way of enforcing explicit signatures of overridden methods but given that the compiler enforces that any signature changes are at least 'safe' then it seems like there is a separate conversation to be had around the solution to that problem.

kungfusheep on 24 Mar 2016

Yeah agreed. If I had to choose, the missing-override/illegal override situation is the more important problem to solve.

rwyborn on 24 Mar 2016

I'm a bit late to the party... I think the whole point of Typescript is to enforce rules at compile-time, not at runtime, otherwise we'd all be using plain Javascript. Also, it's a bit weird to use hacks/kludges to do things that are standard in so many languages.
Should there be an override keyword in Typescript? I certainly believe so. Should it be mandatory? For compatibility reasons I'd say its behavior could be specified with a compiler argument. Should it enforce the exact signature? I think this should be a separate discussion, but I haven't had any problem with the current behavior so far.

armandn on 24 Mar 2016

👍6

The original reason for closing this seems to be that we cannot introduce the breaking change that all overridden methods needs the override specifier, which would make it confusing since the methods not marked with override could also in fact be overrides.

Why not enforce it, either with a compiler option, and/or if there is _at least one_ method marked override in the class, then all methods that are overrides must be marked as such, otherwise it is an error?

alphaleonis on 8 Apr 2016

👍6 😕1

Is it worth reopening this whilst it's up in the air?

On Fri, 8 Apr 2016 at 14:38, Peter Palotas [email protected] wrote:

The original reason for closing this seems to be that we cannot introduce
the breaking change that all overridden methods needs the override
specifier, which would make it confusing since the methods not marked with
'override' could also in fact be overrides.

Why not enforce it, either with a compiler option, and/or if there is at
least 'one' method marked override in the class, then all methods that are
overrides must be marked as such, otherwise it is an error?

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kungfusheep on 8 Apr 2016

👍6

I say please reopen! I'd be happy with a compiler option.

armandn on 8 Apr 2016

👍9

yes - please reopen

jkristia on 8 Apr 2016

👍4

Reopen this!

afromogli on 8 Apr 2016

👍3

Doesnt ES7 require this overriding/overloading multiple methods having same
name?
On Apr 8, 2016 10:56 AM, "Aram Taieb" [email protected] wrote:

Yes, please reopen this!

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fletchsod-developer on 8 Apr 2016

+1 - for me this is the largest gap in type safety that I have in day-to-day TypeScript development.

Every time I implement a React lifecycle method like "componentDidMount" I search for the relevant react documentation page and copy/paste the method name, to ensure that I don't have a typo. I do this because it takes 20 seconds whereas the bugs from a typo are indirect and subtle, and can take much longer to track down.

class with 5 methods, of which 3 are marked override, wouldn't imply that the other 2 aren't overrides. To justify its existence, the modifier would really need to divide the world more cleanly than that.

If this is the major concern, call the keyword check_override to make clear that you're opting in to override checking, and by implication the others methods are _not checked_ rather than _not overridden_.

BernieSumption on 13 Apr 2016

👍3

What about using implements.? Being something like this:

class MyComponent extends React.Component<MyComponentProps, void>{
    implements.componentWillMount(){
        //do my stuff
    }
}

This syntax has some advantages:

It uses an already existing keyword.
After writing implements. the IDE has an excelent oportunity to show an autocompletion popup.
the keyword clarifies that can be used to force checking on abstract methods of base classes but also implemented interfaces.
the syntax is ambiguous enough to be usable also for fields, like this:

class MyComponent<MyComponentProps, MyComponentState> {
    implements.state = {/*auto-completion for MyComponentState here*/};

    implements.componentWillMount(){
        //do my stuff
    }
}

Note: Alternatively we could use base., it's sorter and more intuitive, but maybe more confusing (defining or calling?) and the meaning is not so compatible with interface implementation. Example:

class MyComponent<MyComponentProps, MyComponentState> {
    base.state = {/*auto-completion for MyComponentState here*/};

    base.componentWillMount(){ //DEFINING
        //do my stuff
        base.componentWillMount(); //CALLING
        //do other stuff
    }
}

olmobrutall on 13 Apr 2016

👎5 👍2

I don't think implements sufficiently covers all of the use cases
mentioned previously & it's a little ambiguous. It doesn't give any more
information to an IDE that override couldn't either, so it would seem to
make sense to stick with the terminology many other languages have used to
achieve the same thing.
On Wed, 13 Apr 2016 at 19:06, Olmo [email protected] wrote:

What about using implements.? Being something like this:

class MyComponent extends React.Component{
implements.componentWillMount(){
//do my stuff
}
}

This syntax has some advantages:

It uses an already existing keyword.

After writing implements. the IDE has an excelent oportunity to show
an autocompletion method.

the keyword clarifies that can be used to force checking on abstract
methods of base classes but also implemented interfaces.

the syntax is ambiguous enough to be usable also for fields, like
this:

class MyComponent {
implements.state = {/_auto-completion for MyComponentState here_/};
implements.componentWillMount(){
    //do my stuff
}
}

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kungfusheep on 13 Apr 2016

👍3

The problem with override is that once you use the same keyword you have the same expectations:

it should be mandatory, at least if the method is abstract.
you miss then some virtual keyword to annotate methods that are meant to be overridden but have default behavior.

I think the TS team doesn't want to add so much OO baggage to the language, and I think is a good idea.

By using implements. you have a lightweight syntax for getting the main benefits: auto-complete and compile-time checked name, without inventing new keywords or incrementing the concept count.

Also has the benefit of working for classes and interfaces, and for methods (in the prototype) or direct fields.

olmobrutall on 14 Apr 2016

Ways of making override mandatory have already been discussed in the thread and the solutions aren't different to other features implemented by the compiler.

The virtual keyword doesn't really make sense in the context of the language and neither is it named in a way that is intuitive for people who haven't used languages like C++ before. Perhaps a better solution to provide this type of guard, if needed, would be the final keyword.

I agree language features should not be added hastily that could create 'baggage', but override plugs a legitimate hole in the inheritance system that many other languages have deemed necessary. It's functionality is best achieved with a new keyword, certainly when alternative approaches are to suggest fundamental syntax changes.

kungfusheep on 14 Apr 2016

👍3

What about setting inherited fields vs redefining new ones? React state is a good example.

Or implementing optional interface methods?

olmobrutall on 14 Apr 2016

override could potentially be used on fields, if they're being re-declared
in the subclass body. Optional interface methods aren't overrides so are
outside of the scope of what we're talking about here.

On Thu, 14 Apr 2016 at 11:58, Olmo [email protected] wrote:

What about setting inherited fields vs redefining new ones? React state
is a good example.

Or implementing optional interface methods?

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kungfusheep on 14 Apr 2016

Optional interface methods aren't overrides so are outside of the scope of what we're talking about here.

Optional interface methods are a concept fairly unique to TypeScript as far as I know, and I think a TypeScript implementation of "overrides" should apply to them to.

In the case of React lifecycle methods like componentDidMount, these are optional interface methods that have no implementation in the superclass.

BernieSumption on 14 Apr 2016

In the case of React lifecycle methods like componentDidMount, these are optional interface methods that have no implementation in the superclass.

Exactly, so they don't override anything. I think we're getting confused about what the override keyword is intended to provide here, because if you're just looking for a way of getting better code hinting/intellisense there are other ways that can be achieved without adding new keywords to the language.

kungfusheep on 14 Apr 2016

Guys, with all due respect, can we please stay focused. I think that discussing alternative keywords is counterproductive, especially since the Issue was started with a specific request.

Can we all either agree that we need override and ask nicely the Typescript team to add it or drop the request and let the Issue closed?

armandn on 14 Apr 2016

👍2

I think it's always useful to pose the request in the context of what the problem is, there's always different ways to solve the problem. The sticking point with override was around it being mandatory or not (some making the point that it isn't mandatory in C++). The problem a lot of people have referenced is getting the name right for overridable functions (which may or may not be implemented in the super class) - React's lifecycle functions being the main problem.

If override doesn't work, then maybe we should close this issue and open a more general point about this problem. The general problem here is that the interface contract with a superclass is untyped and unchecked, and that's tripping up developers and it would be great if TS or the tooling can help.

joewood on 14 Apr 2016

👍1

@armandn I don't think our lack of closure or the niceness of our suggestion is what's keeping the request rejected, but the differences between C# and TS semantics:

C# base method override:

Requires override keyword
Creates a new record on VTable
Checks for mandatory abstract/virtual in base method
Checks for identical signature
IDE: Triggers auto-complete after writing override

C# interface implementation:

No keyword necessary, but explicit interface implementation possible using the interface name.
Create a new interface record in the VTable.
Checks for identical signature
IDE: QuickFix for implement interface / implement interface explicitly.

So the behavior in C# are quite different depending if you ask about classes or interfaces, but in any case you get the main three benefits:

Checking for identical signature
Checking that the method can/should be overridden (misspelling in method name)
IDE support writing the function

With slightly different semantics, we already have 1) in TS, unfortunately 2) and 3) are missing. The reason override was rejected, in my opinion, is that a similar syntax assumes a similar behavior, and this not desirable because:

A class with 5 methods, of which 3 are marked override, wouldn't imply that the other 2 aren't overrides.

It happens that we already have 1) 2) and 3) when writing _object literals_, but not when writing class members that extend other classes or implement interfaces.

With this in mind I think we can all agree on this semantics:

The _keyword_ should be ambiguous enough to avoid the 'split world' problem. (i.e.: check or super., or MyInterface.)
No checks for abstract/virtual but checks for member existence in the base class / implemented interfaces. (Benefit 2)
Checks for similar-enough signature compatibility as TS is doing so far. (Benefit 1)
IDE: Triggers a auto-complete after the keyword. (Benefit 3)

Additionally, I think this two are necessary for completeness of the solution*:

It should work for Classes and Interfaces, because TS is mainly interface based and classes are a shortcut for prototypical inheritance. Necessary considering optional interface methods.
It should work for Methods and Fields, because methods are just functions residing in a field.

This two points are useful in the very-real use case of React component implementation:

``` C#
class MyComponent {
implements.state = {/auto-completion for MyComponentState here/};

implements.componentWillMount(){
    //do my stuff
}

}
```

The Annotation-based solution from @RyanCavanaugh is not enough because:

It won't work with interfaces.
It won't work with fields.
Assuming a Roslyn-like infrastructure for helping with the tooling, there is no way to add a QuickFix after writing auto-complete list after writing @override.

Given the semantics, it's just about choosing the right syntax. Here some alternatives:

override componentWillMount(): Intuitive but misleading.
check componentWillMount(): Explicit but keyword-consuming.
super componentWillMount():
implements componentWillMount():
super.componentWillMount():
implements.componentWillMount():
this.componentWillMount():
ReactComponent.componentWillMount():

Opinions?

olmobrutall on 14 Apr 2016

👍2

@olmobrutall good summary. Couple of points:

One keyword option (taken from C#) would be new - indicating a new slot:

class MyComp extends React.Component<IProps,IState> {
...
    new componentWillMount() { ... }
    componentWillMount() { ...} // would compile, maybe unless strict mode is enabled
    new componentwillmount() { ... } <-- error

My other point is the issue with mandatory nature of using the above. As a contract between the parent super class and the derived class it makes sense to specify what are interface points where the above syntax would be valid. These are really internal extensions points for the super class, so something like:

class Component<P,S> {
    extendable componentWillMount() {...}
}

The same would apply to the interface too.

joewood on 14 Apr 2016

👍1

Thanks :)

What about just writing this?

class MyComponent<MyComponentProps, MyComponentState> {
    this.state = {/*auto-completion for MyComponentState here*/};

    this.componentWillMount(){
        //do my stuff
    }
}

About extendable, there's already abstract in TS 1.6, and adding virtual will maybe create again the split world problem?

olmobrutall on 14 Apr 2016

Right, I thought about abstract but there may be an implementation in the super class, so it doesn't really make sense. Likewise with virtual, as that would imply non-virtual members are not virtual - which is misleading.

this. works, I guess you could even have (as a long form):

   this.componentWillMount = () => { }

The only issue with this is that it should only be scoped to earmarked extension points, not all members of the base class.

joewood on 14 Apr 2016

what is going on...

TypeScript isn't and never has been the javascript version of C#. So the reason isn't because the suggested functionality differs from the semantics of C#. The reasons for closure as stated by Ryan and then clarified by Daniel R were

As Ryan explained, the issue is that marking a method as an override doesn't imply that another method isn't an override. The only way that it would make sense is if all overrides needed to be marked with an override keyword (which if we mandated, would be a breaking change).

Yet you're still persisting with your problems around autocomplete. Autocomplete doesn't need a new keyword in the language to provide you with improved suggestions.

The reason this thread exists was to get compiler errors when a function is illegally overridden or when a method was declared to be an override but didn't actually override a function in a base class. It's a simple and well defined concept across many languages that also support most if not more language features typescript has to offer. It doesn't need to solve all the worlds problems, it just needs to be the override keyword, for overrides.

More people have since shown interest in the original proposal, so lets stick to the topic the issue was raised for and raise new issues for new ideas.

kungfusheep on 14 Apr 2016

👍3

TypeScript isn't and never has been the javascript version of C#.

I'm comparing it with C# as a reference language, since I assume this is the behavior you guys are assuming.

Autocomplete doesn't need a new keyword in the language to provide you with improved suggestions.

How you suggest it to be triggered then? If you show a autocomplete combobox when writing a random name in a class context will be very annoying when we just want to declare a new field or method.

The reason this thread exists was to get compiler errors when a function is illegally overridden or when a method was declared to be an override but didn't actually override a function in a base class.

I absolutely included this use case, under Benefit 2.

It doesn't need to solve all the worlds problems, it just needs to be the override keyword, for overrides.

So your suggestion is to fix _one step at a time_ instead of moving one step back and look at similar/related problems?. That maybe a good idea for your Scrum Board but not for designing languages.

The reason they are conservative about adding the keyword is that they can not remove features from a language.

Some design mistakes in C# because of lack of completion:

Unsafe Array co-variance / contra-variance.
var only working for variable types, not for automatic generic parameters or return types. Mayble autowill be a better keyword like in C++?

Just try to use React for a second and you'll see the other side of the picture.

olmobrutall on 15 Apr 2016

👎1

Overriding a method that's already been implemented in a base class and implementing an interface method are _two completely different things_. So yes, what's being suggested is to fix one of those scenarios with a dedicated keyword instead of trying to come up with some Swiss-Army keyword.

What good is a keyword that can mean any one of 3 different things to developers reading some code for the first time? It's ambiguous and confusing, especially if you're talking about using a keyword like this which already does other (totally unrelated!) things in the language - it couldn't be more generic, it's almost useless.

If your main concern is auto-complete, editors have enough information _now_ to be able to suggest methods from base classes and implemented interfaces 'as you type'.

kungfusheep on 15 Apr 2016

👍3

Overriding a method that's already been implemented in a base class and implementing an interface method are two completely different things.

In the general case yes, but we're not talking about implementing any interface method. We're talking about an optional interface method _where the parent class implements the interface_. In this case you can say that 1) interface permits the method to be implemented as undefined, 2) the parent class has an undefined implementation, and 3) the child class is overriding the undefined implementation with a method implementation.

BernieSumption on 15 Apr 2016

👍2

@olmobrutall I think your comment about designing languages and how it is not a scrum board is a little self-serving. I have seen about four updates to TS in the space of under a year.

If the language design was as well considered as you imply it should be, then there would already be a language spec document telling us exactly how overrides should work, and we mightn't even be having this conversation.

I don't make this comment with any denigration of the TS developers/designers, because TS is already excellent and I would dread having to use standard JS instead.

Yes TS is not C# and it's not C++. But a number of languages have chosen the override keyword to meet the objectives discussed here so it seems counterproductive to suggest totally alien syntax.

The chief issue seems to be not wanting to introduce a breaking change. The simple answer is a compiler flag, end of story. For some people like me, an optional override keyword is useless. For others they want to embellish their code incrementally. Compiler flag solves the dilemma.

Signature differences are a different conversation. The new keyword appears unnecessary because JS can't support multiple methods of the same name (unless TS creates signature-derived mangled names a'la C++, which is highly unlikely).

kevmeister68 on 15 Apr 2016

👍7

I have seen about four updates to TS in the space of under a year.

I don't mean you can not be fast and iterate quickly. I'm as happy as anybody that ES6 and TS are evolving fast. What I mean is that you have to try to predict the future, to avoid putting the language in a dead end.

I could agree on using override keyword. With proper arguments even keeping fields and interfaces out of the scope, but I can not agree with the '_let's stay focused and solve just this particular problem the way other languages do it without thinking too much_' argument.

But a number of languages have chosen the override keyword to meet the objectives discussed here so it seems counterproductive to suggest totally alien syntax.

None of this languages have prototypal inheritance or optional method (methods that are neither abstract or virtual, they just could _not exist_ at runtime), and this are related problems that have to be discussed (and maybe discarded) before making a commitment.

Put another way: let's say we do as you seem to suggest and we implement override without thinking to much. Then me, or anybody else using TSX, adds an issue with why override doesn't work with React components. Whats your plan?

olmobrutall on 15 Apr 2016

❤1 🎉1 👍1

In the general case yes, but we're not talking about implementing any interface method. We're talking about an optional interface method where the parent class implements the interface.

It doesn't matter where the interface was set up, the fact is they are not the same thing and so shouldn't share a keyword because the _intent_ of the program is not clear.

You could, for example, be overriding a method which had been implemented for interface compliance in a base class; If we were to put all our eggs in one keyword for these two different things, how would anyone then know if this was the initial declaration of that function or an override to one previously defined in a base class? You wouldn't, and it wouldn't be possible to know without further inspection of the base class - which may even be in a 3rd party .d.ts file & thus making it an absolute nightmare to find, depending how deep in the inheritance chain the function was originally implemented.

Put another way: let's say we do as you seem to suggest and we implement override without thinking to much. Then me, or anybody else using TSX, adds an issue with why override doesn't work with React components. Whats your plan?

Why does this need to fix React? If React has a different problem to what this is trying to solve then I can't for the life of me fathom why override needs to fix it? Have you tried opening another issue to suggest something be done about interface implementation?

I wouldn't agree that enough thought hasn't been put in to this. We're suggesting a tried and tested technique that's been successful in every other language I can think of that's implemented it.

kungfusheep on 15 Apr 2016

the fact is they are not the same thing and so shouldn't share a keyword because the intent of the program is not clear.

Are not? Look at this two alternative definitions of BaseClass

class BaseClass {
     abstract myMethod(); 
}

interface ISomeInterface {
     myMethod?(); 
}

class BaseClass extends ISomeInterface {
}

And then in your code you do:

``` C#
class ConcreteClass {
override myMethod() {
// Do stuff
}
}

You think it should work in just one case and not in the other? The effect is going to be 100% identical in Javascript (creating a new method in ConcreteClass prototype), from the external interface and from the tooling perspective. 

Even more, maybe you want to capture `this` inside of the method, implementing it with a lambda (useful for React event handling). In this case you'll write something like this:

``` C#
class ConcreteClass {
    override myMethod = () => { 
         // Do stuff
    }
}

The behavior will be again identical if the method is abstract or comes from the interface: add a field in the class with a lambda implementing it. But it looks a little bit strange to override a field, since you're just assigning a value.

Not let's see it using super. (my favorite syntax right now, but I'm open to alternatives).

``` C#
class ConcreteClass {
super.myMethod() { //method in prototype
// Do stuff
}

super.myMethod = () => {  //method in lambda
     // Do stuff
}

}
```

Now the concept is conceptually simpler: My super class says that there is a method or field and the ConcreteClass can define it in the prototype / assign it / read it / call it.

Why does this need to fix React?

Is not just react, look at angular:

React: 58 interfaces and 3 classes.
Angular: 108 interfaces and 11 classes.

Of course most of the interfaces are not meant to be implemented, neither all the classes to be overriden, but one thing is clear: in Typescript interfaces are more important than classes.

Have you tried opening another issue to suggest something be done about interface implementation?

How should I call it? override for interface and fields?

We're suggesting a tried and tested technique that's been successful in every other language I can think of.

The languages you have in mind are quite different. They have inheritance based in a static VTable.

In Typescript a class is just an interface + automatic prototype inheritance of methods. And methods are just fields with a function inside.

In order to adapt the override feature to TS this two fundamental differences have to be considered.

Please @kungfusheep make the effort to think about a solution to my problem. If you want to add different keywords and implement them in a second stage is O.K., but take a second to imagine how it should be.

olmobrutall on 15 Apr 2016

👍2

I can't think of another way to say what I've already said. They are not the same. They are similar, but not the same. Please see this comment by one of the TS devs RE: the readonly keyword - https://github.com/Microsoft/TypeScript/pull/6532#issuecomment-179563753 - which strengthens what I'm saying.

kungfusheep on 16 Apr 2016

I agree with the general idea, but let's see in practice:

class MyComponent extends React.Component<{ prop : number }, { value: string; }> {

    //assign a field defined in the base class without re-defining it (you want type-checking)
    assign state = { value : number}; 

    //optional method defined in an interface implemented by the base class    
    implement componentDidMount(){ 
    }

    //abstract method defined in the base class 
    override render(){  
    }
}

This looks like VB or Cobol, doesn't it?

olmobrutall on 16 Apr 2016

It looks like it makes sense, at least.

Consider this example, were there only the override (or just one) keyword.

interface IDo {
    do?() : void;
}
class Component implements IDo {
    protected commitState() : void {
        /// do something
    }
    override public do() : void {
        /// base implements 'do' in this case
    }
}

Now lets implement our own component using what we just wrote.

class MyComponent extends Component {
    override protected commitState(){
        /// do our own thing here
        super.commitState();
    }
    override do() : void {
        /// this is ambiguous. Am I implementing this from an interface or overriding a base method? I have no way of knowing. 
    }

}

kungfusheep on 16 Apr 2016

👎1 👍1

One way of knowing would be the type of super:

  override do() : void {
        super.do(); // this compiles, if it was an interface then super wouldn't support `do`
    }

joewood on 16 Apr 2016

exactly! which means the design is wrong. there shouldn't be an investigation involved with skimming code, it should just make sense when you read it.

kungfusheep on 16 Apr 2016

👍2

this is ambiguous. Am I implementing this from an interface or overriding a base method? I have no way of knowing.

What's the difference in practice? The object has just one space of names and you can only place one lambda in the do field. There's no way of explicitly implementing an interface anyway. The implementation is going to be:

MyComponent.prototype.do = function (){
    //your stuff
}

independently of what you write.

olmobrutall on 16 Apr 2016

👍1

It doesn't matter what the output is. You could be either intentionally or unintentionally overriding some functionality in a base class, but there is no intent in a keyword that is ambiguous.

kungfusheep on 16 Apr 2016

What error or unexpected behavior will be solved by having two keywords?

olmobrutall on 17 Apr 2016

👍1

Come on now mate. You're obviously a clever guy. I've just said "unintentionally overriding some functionality in a base class"; can we not infer from this any unexpected behaviour that could have potentially just occurred?

To be clear, I'm not proposing turning this issue into a proposal for two keywords. This issue is for the override keyword - anything else will need a new proposal and its own discussion on semantics.

kungfusheep on 17 Apr 2016

To be clear, I'm not proposing turning this issue into a proposal for two keywords. This issue is for the override keyword - anything else will need a new proposal and its own discussion on semantics.

It doesn't really matter in how many issues it should be discussed, or from whom the idea comes. You propose to split two very related thinks and don't even consider a consistent syntax.

The arguments for whether we need 1, 2 or 3 keywords belong to this thread and is not finished (...but becoming repetitive). Then maybe we can discuss the syntax in another thread (because the semantics are going to be identical anyway :P).

In my example:

class MyComponent extends React.Component<{ prop : number }, { value: string; }> {

    //assign a field defined in the base class without re-defining it (you want type-checking)
    assign state = { value : number}; 

    //optional method defined in an interface implemented by the base class    
    implement componentDidMount(){ 
    }

    //abstract method defined in the base class 
    override render(){  
    }
}

Don't assign, implement and override do exactly the same thing: Check that the name exist (in the base class, the implemented interfaces, the interfaces implemented by the base class, etc...).

If there's a name conflict between base classes and some implemented interfaces you'll get an compile-time error whether with 1, 2 or no keyword at all.

olmobrutall on 17 Apr 2016

👍1

Also think about the object literal:

var mc = new MyComponent(); 
mc.state = null;
mc.componentDidMount =null;
mc.render = null;

With exactly the same syntax I can re-assign fields or method independently if they come from the base class, direct interface implementations or interfaces implemented in the base class.

olmobrutall on 17 Apr 2016

Don't assign, implement and override do exactly the same thing: Check that the name exist (in the base class, the implemented interfaces, the interfaces implemented by the base class, etc...).

You've just described 3 different scenarios there, so obviously they're not the same. I have a feeling I could describe why they're different to you all day and you'd still be sat arguing that they're not, so I'm going to bow out of this particular line of discussion for now. There's nothing to say the TS guys are still considering this at the moment anyway.

kungfusheep on 17 Apr 2016

With the closure of #6118 I think there's reason to discuss if the problems there and the problems here can be addressed simultaneously.

RyanCavanaugh on 3 May 2016

I was not aware of https://github.com/Microsoft/TypeScript/pull/6118. The idea looks like a possible alternative to adding override.

If I understood the problem properly, the issue is that you can have more than one base classes / interfaces with compatible but not identical member declarations, and they have to be unified when being initialized in the child class without a type.

Without having a good idea of the consequences, I would be happy if:

the member will produce a compile-time error that requires explicit type declaration on the child class
the member will take the intersection of all the possible types.

More important IMO would be to have some way of triggering auto-completion when writing class members (Ctrl+Space). When the cursor is directly inside of a class, you could be defining new members of re-defining inherited ones, so the auto-completion can not be too aggressive, but with manual triggering the behavior should be OK.

olmobrutall on 3 May 2016

Regarding @RyanCavanaugh comments:

We definitely understand the use cases here. The problem is that adding it at this stage in the language adds more confusion than it removes. A class with 5 methods, of which 3 are marked override, wouldn't imply that the other 2 aren't overrides. To justify its existence, the modifier would really need to divide the world more cleanly than that.

Typing a variable as any doesn't imply that some other variable is or isn't also any. But, there is a compiler flat --no-implicit-any to enforce that we explicitly declare it. We could equally have a --no-implicit-override, which I for one would turn on if it were available.

Having an override keyword that is used gives developers an enormous amount of insight when reading code that they are unfamiliar with, and the ability to enforce it would give some additional compile time control.

For all the +1ers -- can you talk about what's not sufficient about the decorator solution shown above?

Is there any way in which a decorator a better solution than an override keyword? There are many reasons why it is worse: 1) It adds runtime overhead however small; 2) It's not a compile time check; 3) I have to include this code to every one of my libraries; 4) There is not way for this to catch functions that are missing the override keyword.

Let's give an example. I have a library with three classes ChildA, ChildB, Base. I've added some method doSomething() to ChildA and ChildB. After some refactoring, I've added some additional logic, optimized, and moved doSomething() to the Base class. Meanwhile, I have another project which depends on my library. There I have ChildC with doSomething(). There is no way when I update my dependencies to find out that ChildC is now implicitly overriding doSomething(), but in an unoptimized way that is also missing some checks. That is why an @overrides decorator will never be sufficient.

What we need is an override keyword, and a --no-implicit-override compiler flag.

eggers on 4 May 2016

👍6 ❤2

An override keyword would help me a lot since I use in my project a simple hierarchy of base classes to create all my components. My problem lies in the fact that these components may need to declare a method to be used somewhere else, and this method may or may not be defined in a parent class and may or may not already do stuff that I need.

For example, let's say that a function validate takes a class with a getValue() method as parameter. To build this class, I can inherit another class that could already define this getValue() method, but I can't really know this unless I look at its source code. What I'd instinctively do is implement this method in my own class, and as long as the signature is correct no one will tell me anything.

But maybe I shouldn't have done that. The following possibilities all suppose that I did an implicit override:

The base class already defined this method just like I did, so I wrote a function for nothing. Not that much of a problem.
I incorrectly rewrote the function, most of the time because I forgot to do some non-obvious stuff that was already handled by the base class. What I really needed to do here is call super in my override, but no one suggested me to do so.

Having a mandatory override keyword would have told me "hey, you're overriding, so maybe you should check what the original method looks like before doing your stuff". That would greatly improve my experience with inheritance.

Of course, as suggested, it should be placed under a --no-implicit-override flag since it would be a breaking change and that most people do not care that much about all this.

I like the comparaison @eggers made with any and --no-implicit-any because it's the same kind of annotation and it would work in the exact same way.

JabX on 4 May 2016

👍3

@olmobrutall I was looking at some of your talk about overriding abstract methods & interface methods.

If my opinion, override implies the existence of a super. Neither abstract methods nor methods defined in an interface can be called via a super. call, and so should not be overrideable (there is nothing to override). Instead if we do something more explicit for those cases, it should be an implements keyword. But, that would be a separate feature discussion.

eggers on 4 May 2016

👍1

Here are the problems as I see them, ranked most important to least. Did I miss anything?

Failure to override

It's easy to _think_ you're overriding a base class method when you're not:

class Base {
  hasFilename(f: string) { return true; }
}
class Derived extends Base {
  // oops
  hasFileName(f: string) { return false; }
}

This is probably the biggest problem.

Failure to implement

This is very closely related, especially when the implemented interface has optional properties:

interface NeatMethods {
  hasFilename?(f: string): boolean;
}
class Mine implements NeatMethods {
  // oops
  hasFileName(f: string) { return false; }
}

This is a less important problem than _failure to override_, but it's still bad.

Accidental override

It's possible to override a base class method without realizing it

class Base {
  hasFilename(f: string) { return true; }
}
class Derived extends Base {
  // I didn't know there was a base method with this name, so oops?
  hasFilename(f: string) { return true; }
}

This should be relatively rare just because the space of possible method names is very large, and the odds that you'd also write a compatible signature _and_ not mean to have been doing this in the first place are low.

Accidental `any`s

It's easy to think that override methods will get the parameter types of their base:

class Base {
  hasFilename(f: string) { return true; }
}
class Derived extends Base {
  // oops
  hasFilename(f) { return f.lentgh > 0; }
}

We tried to type these parameters automatically but ran into problems. If hasFilename were explicitly marked override we might be able to solve those problems more easily.

Readability

It's not immediately clear when a method is overriding a base class method and when it's not. This seems like a smaller problem because there are reasonable workarounds available today (comments, decorators).

Editor experience

You have to manually type out base method names when writing derived class override methods, which is annoying. We could easily fix this by always providing those names in the completion list (I think we actually have a bug on this already), so we don't really need a language feature to fix this problem.

Non-problems

Listing these out as things that either belong in a separate issue or simply aren't going to happen:

Exact signature matching -- this isn't something that should be mixed in with override, and it really does have undesirable semantics in many good scenarios
Insufficiently exotic syntax (e.g. implements.foo = ...). No need to bikeshed here

RyanCavanaugh on 4 May 2016

👍15

@RyanCavanaugh I agree with all of the above in about that order as well. Just as a comment, I don't think that the override keyword should be solving the "failure to implement" problem. As I said above, I think that problem should be solved by a different keyword (e.g. implements) as part of a different ticket. (override should imply a super. method)

eggers on 4 May 2016

👍4

@RyanCavanaugh I agree with all the points but I don't see any reference to the also very related problem of initialized fields declared in a parent type without overriding the type (and then loosing type checking). I think the feature should not be confined to method declarations in a language where methods are just functions in object fields.

@eggers even if at the end the end two keywords are needed, the semantics will be very similar and I think the features should be discussed together.

override should imply a super. method

In C# override can (and must) be used also for abstract methods (with no .super). In Java @override is an attribute. Of course they are different language but with similar keywords you expect similar behaviors.

olmobrutall on 5 May 2016

I agree with @RyanCavanaugh 's points, though I'd say the "accidental override" problem might be a little more common than he believes (especially when dealing with extending a class that already extends something else, like a React component that would already define a componentWillMount method in the first extension).

I believe though, like @eggers said, that the "failure to implement" issue is something pretty different, and it would feel weird to use an override keyword for a method that doesn't exist in a parent class. I know these are different languages with different problematics, but in C# override isn't used for interfaces. I would suggest, if we could get a --no-implicit-override flag, that interface methods would have to be prefixed with the interface name (which would look a lot like C# and thus feel more natural).

Something like

interface IBase {
    method1?(): void
}

class Base {
    method2() { return true; }
}

class Test extends Base implements IBase {
    IBase.method1() { }
    override method2() { return true; }
}

JabX on 5 May 2016

I think @RyanCavanaugh lists the fundamental problems. I would complement that with "What are the disagreements":

Is declaring a method to match an interface considered an override? For example:

    interface IDrawable
    {
        draw?( centerPoint: Point ): void;
    }

    class Square implements IDrawable
    {
        draw( centerPoint: Point ): void; // is this an override?
    }

is declaring a property to match an interface considered an override?

    interface IPoint2
    {
        x?: number;
        y?: number;
    }

    class Circle implements IPoint2
    {
        x: number; // is this an override?
        y: number; // is this an override?
        radius: number;
    }

Is there a need for some kind of implements keyword, to handle the above cases instead of an override keyword, and the form it would take.

kevmeister68 on 5 May 2016

@kevmeister68 thanks for explicitly stating the disagreements.

One thing: you have to make the interface members optional to really show the problem, like this the typescript compiler will complain when a field or method is not implemented, solving "Failure to implement".

olmobrutall on 5 May 2016

@olmobrutall Thanks for that. I've never declared a method optional - can it be (I come from a C# background and there is no such concept)? I've updated the examples I listed above to change the member variables to optional - is that better?

kevmeister68 on 5 May 2016

@kevmeister68 also the draw method in IDrawable :)

olmobrutall on 5 May 2016

@RyanCavanaugh

Insufficiently exotic syntax (e.g. implements.foo = ...). No need to bikeshed here

Thanks for teaching me a new expression. I don't see a lot of problems in the semantics of the feature:

We all want compile-time errors if the method does not exist
We all want compile-time errors the type does not match.
We also want that the parameters are implicitly typed to the parent one, like lambda expressions do.
We want some IDE help to write the method properly.

Most of the problems rely on the syntax and the behaviours that they impliy:

Optional members in Interface vs members in Base classes
Methods vs fields (don't know where lambdas will be)

Let's compare the tree more promising syntaxes:

override / implements

class Person{
    dateOfBirth: Date;

    abstract talk();
    walk(){ //...}
}

interface ICanFly{
    fly?();
    altitude?: number;
}


class SuperMan extends Person implements ICanFly {
     dateOfBirth = new Date(); //what goes here?

     override talk(){/*...*/}
     walk = () => {/* force 'this' to be captured*/}  //what goes here

     implements fly() {/*...*/}
     altitude = 1000; //what goes here?
}

Advantages:

It's natural for programmers with OO background.
Feels right when comparing with extends / implements.

Disadvantages:

Doesn't provide a solution to the field problem, none override or implements feels right. Maybe super., but then what we do with interfaces?
If the methods are overridden using a lambda (useful to capture this) of a function() the same problems happens.

override / `InterfaceName.`

class Person{
    dateOfBirth: Date;

    abstract talk();
    walk(){ //...}
}

interface ICanFly{
    fly?();
    altitude?: number;
}


class SuperMan extends Person implements ICanFly {
     dateOfBirth = new Date(); //what goes here?

     override talk(){/*...*/}
     walk = () => {/* force 'this' to be captured*/}  //what goes here

     ICanFly.fly() {/*...*/}
     ICanFly.altitude = 1000; //what goes here?
}

Advantages:

Is also natural for programmers with OO background.
Solves the field problem for interfaces, but not for classes, but we could use super. for them.

Disadvantages:

Interface names can be long, specially with generics, and showing the auto-competition list will also be problematic, requiring some Alt+Space to make it explicit.
Makes it looks like you can implement two members with the same name from different interfaces independently. This works in C# but won't work in Javascript.

`this.`

class Person{
    dateOfBirth: Date;

    abstract talk();
    walk(){ //...}
}

interface ICanFly{
    fly?();
    altitude?: number;
}


class SuperMan extends Person implements ICanFly {
     this.dateOfBirth = new Date();

     this.talk(){/*...*/}
     this.walk = () => {/* force 'this' to be captured*/} 

     this.fly() {/*...*/}
     this.altitude = 1000;
}

Advantages:

Solves classes, interfaces, methods and fields.
Uses (abuses?) just one pre-existing keyword.
Using this. to trigger auto-completion feels natural.
Makes clear that the object is just one namespace, and you can only have one thing for each name.

Disadvantages:

Looks like an expression, not a declaration, making it hard to parse for non-trained eyes.

olmobrutall on 5 May 2016

Whilst failure to implement a non-optional interface method will cause a compiler error, if the interface changes at some point in the future (lets say a method is removed) there will be no warning for all classes that implemented that method. This might not be as big an issue as optional's but I think it's fair to say the scope of this goes beyond them.

I do however, still believe override is a distinctly different thing and potentially having two keywords rather than one would better convey the intent of the program.

For example, consider a scenario where a developer _believes_ they are implementing an interface method when in-fact they're overriding the method which has already been declared in a base class. With two keywords the compiler can prevent this kind of mistake and throw an error to the tone of method already implemented in a base class.

interface IDelegate {
    execute?() : void;
}

class Base implements IDelegate {
    implement public execute() : void { /// fine, this is correctly implementing execute
    }
}

class Derived extends Base {
    implement public execute() : void { 
/// ERROR: `method "execute():void" already implemented in a base class`
    }
}

kungfusheep on 5 May 2016

I don't know if this is relevant in JS, but class fields are supposed to be private in OO, so I don't think we need to be overriding fields explicitly since the fact that they're private already prevent us to override altogether.

Instance methods are fields though, and from what I gather a lot of people use them instead of prototype methods. About that,

class Person{
    walk(){ //...}
}
class SuperMan extends Person  {
     walk = () => {/* force 'this' to be captured*/}
}

is a compiler error, because walk is a prototype method in Person and an instance method in SuperMan.

Anyway, i'm not sure override would be a fit here, because well, we don't override fields. Again, it would look like C#, but I'd rather use the new keyword instead of override here. Because it's not the same thing as a method override (I can call super.myMethod in an override, not here).

My preferred solution would then be something like (assuming we're in strict override mode):

class Person{
    dateOfBirth: Date;
    talk() { }
    walk = () => { }
}

interface ICanFly {
    fly?();
    altitude?: number;
}

class SuperMan extends Person implements ICanFly {
     new dateOfBirth = new Date();
     override talk() { }
     new walk = () => { }

     implements fly() {/*...*/}
     implements altitude = 1000;
}

My main concern is about interfaces though. We shouldn't have to write implements for non optional interface members, because we'll be already caught by the compiler. Then, if we do so, there'll be a confusion between what is from an interface and what isn't, since not all interfaces members would be prefixed by implements. And that word is a mouthful. I'm not ready to write something like this:

class C extends React.Component {
    implements componentWillMount() { }
    implements componentDidMount() { }
    implements componentWillReceiveProps(props) { }
    /// ... and the list goes on
}

I proposed to prefix with the interface name earlier but @olmobrutall showed me that it was a worse idea.

Anyway, I'm pretty convinced that we'll need 3 different new keywords to properly tackle this.

I also don't think that it's necessary to implicitly type the overrides since the compiler will already prevent us to write something that's not compatible, especially because it is apparently difficult to do right.

JabX on 5 May 2016

Isn't new, override and implement too much keyword overhead for essentially the same JS semantics? Even if in C# they are different things there is virtual no difference in JS/TS.

It's also quite ambiguous:

Why fields are new for classes but implements for interfaces?
If you're changing a method from a base class that was implemented with an interface what should you use? I can see four possibilities: override, implements, any of the two or both at the same time?

Also think about this:

class Animal {
}

class Human extends Animal {
}

class Habitat {
    owner: Animal;
}

class House extends Habitat {
    owner = new Human();
}

var house = new House();
house.owner = new Dog(); //Should this be allowed??

The question is:

Does owner = new Human(); re-define the field with a new (but compatible) type, or just assigns a value.

I think in general you re-defined the field except if you using the _magic keyword_. My preference is for this. right now.

class House extends Habitat {
    this.owner = new Human(); //just setting a value, the type is still Animal
}

olmobrutall on 5 May 2016

@olmobrutall That might indeed be a bit much keyword overhead, but all 3 are indeed _different_ things.

override would apply to methods (defined on the prototype), meaning that it does _not_ erase the original method, which is still accessible behind super.
new would apply to fields, and mean that the original field has been erased by the new one.
implements would apply to anything from an interface, and mean that it does not erase or replace anything that already existed in a parent class, because an interface "doesn't exist".

If you're changing a method from a base class that was implemented with an interface what should you use? I can see four possibilities: override , implements , any of the two or both at the same time?

It seems pretty logical to me that it would be override since that what you're effectively doing here. implements would mean that you're implementing something from the interface that doesn't exist otherwise. In a sense, override and new would have priority over implements.

And about your field override exemple, nothing should change about how it works today. I'm not sure what happens here, but whatever it is it shouldn't change (or maybe it should, but that's not what we're discussing here).

JabX on 5 May 2016

I feel that override would be suitable for both base methods and properties, including abstract ones (explained below).

new is an interesting idea in concept, but this particular keyword may be confused with class instantiation, so it may give the false impression it would only work for classes, despite the fact that properties can have primitive, interface, union or even function types. Perhaps a different keyword like reassign could work better there, but it has the problem that it may give a false idea in the case the value is only re-declared but not actually assigned with anything in the derived class (new may have that problem as well). I think redefine is also interesting, but could lead to the mistaken expectation that the 'redefined' property could also have a different type than the base one, so I'm not sure.. (_edit: actually I checked and it could have a different type as long as the new one is a subtype of the base one, so this may not be that bad_).

implement (I prefer this particular verb form for consistency with override) seems to work for interfaces. I believe it could also technically work for abstract base methods as well, but using override could feel more consistent, despite the slightly different semantics. Another reason is that it would make it a bit inconvenient to change a method from abstract to non-abstract, as one would need and go to all the derived classes and change override to implement.

There could be better ideas, but that's all I have at this point..

malibuzios on 5 May 2016

I proposed the keyword new because it's the one C# uses for this exact feature, but I agree this isn't the best one. implement is indeed a better choice over implements. I don't think we should use it for abstract methods since they're part of a base class and not an interface. override + new -> base class, implement -> interface. That seems clearer.

JabX on 5 May 2016

@JabX

About overriding prototype with instance field

I've checked and you're right:

class Person{
    walk(){ //...}
}
class SuperMan extends Person  {
     walk = () => {/* force 'this' to be captured*/}
}

Fails with Compiler error: Class 'Person' defines instance member function 'walk', but extended class 'SuperMan' defines it as instance member property.

I don't really see the reason to fail in this case, since the parent type contract is fulfilled and you can write this anyway:

var p = new SuperMan();
p.walk = () => { };

Or even

class SuperMan extends Person {
    constructor() {
        super();
        this.walk = () => { };
    }
}

About `override`

override would apply to methods (defined on the prototype), meaning that it does not erase the original method, which is still accessible behind super.

That's actually an argument. There is least _some_ observable difference between override and implements... but not quite.

Both override and implements are implemented in the prototype, being able to use super is independent, because you call super.walk() not just super(), and is available in every method ( overrides, implements, news and normal definitions).

class SuperMan extends Person implements ICanFly {
     new dateOfBirth = new Date();
     override talk() { } //goes to prototype
     new walk = () => { }

     implements fly() {/*...*/}  //also goes to the prototype
     implements altitude = 1000;
}

And being able to use super.walk() also works if you assign to the instance

class SuperMan extends Person {
    constructor() {
        super();
        this.walk = () => { super.walk(); };
    }

    //or with the this. syntax
    this.walk = () => { super.walk(); };
}

There's already a clear way to differentiate prototype fields from instance fields and is the = token.

class SuperMan extends Person implements ICanFly {
     this.dateOfBirth = new Date(); //instance
     this.talk() { } //prototype
     this.walk = () => { } //instance

     this.fly() {/*...*/}  //prototype
     this.altitude = 1000; //instance
}

With the this. syntax the problem is solved more elegantly:

this. means check my type (base classes and implemented interfaces).
= means assign to the instance instead of the prototype.

About `New`

new would apply to fields, and mean that the original field has been erased by the new one.

Take into account that you can not change the field or method with a different type because you will break the type system. In C# or Java when you do new the new method will be used only on statically dispatched calls to the new type. In Javascript all the calls will be dynamic and if you change the type the code will likely break at run-time (Coercing the type could be allowed for practical purposes however, but not widening).

class Person {
    walk() { }

    run() {
        this.walk();
        this.walk();
        this.walk();
    }
}

class SuperMan extends Person {
    new walk(destination: string) { } //Even if you write `new` this code will break
}

So more than new the keyword should be assign, because this is the only type-safe thing you can do:

class Person{
    dateOfBirth: Date;
}

class SuperMan extends Person implements ICanFly {
     assign dateOfBirth = new Date();
}

Note that reassign doesn't make sense, because Person only declares the field but doesn't set any value on it.

Writing assign seems redundant however, it's clear that we're assigning because we have a = at the other side.

Again the this. syntax solves the problem gracefully:

class Person{
    dateOfBirth: Date;
}

class SuperMan extends Person implements ICanFly {
     this.dateOfBirth = new Date();
}

olmobrutall on 5 May 2016

I'm not sure how you apply this to fields in a way that makes sense.

We're talking about adding a keyword that is only applicable in the class body, yet fields can be reassigned at _any point_ during the instances lifetime.

kungfusheep on 5 May 2016

Typescript already allows you to initialize fields in the class body:

class Person {
    dateOfBirth : new Date();
}

It also allows you to re-initialize fields declared in the parent class, but the situation bad. Of course you could write the name wrongly (similar problem to override) but the type is also erased. This means that:

class Person {
    fullName: { firstName: string; lastName?: string };
}

class SuperMan extends Person {
    fullName = { firstName: "Clark" };

    bla() {
        this.fullName.lastName; //Error
    }
}

This code fails with: Property 'lastName' does not exist on type '{ firstName: string; }'. because the original type has been erased!.

We're talking about adding a keyword that is only applicable in the class body, yet fields can be reassigned at any point during the instances lifetime.

Also methods:

class Person {
    talk() { }
}

class SuperMan extends Person {

    talk() { }

    changeMe(){
        this.talk = () => { };      
    }

    changeMyPrototype() {
        SuperMan.prototype.talk = () => { };
    }
}

olmobrutall on 5 May 2016

@kungfusheep I agree, fields can be reassigned, but so do methods on the prototype.
The main reason why we would need a keyword for "overriding" fields is because instance methods _are_ fields and they're widely used instead of proper prototype methods because they're lambdas and thus autobind the context.

@olmobrutall

About overriding methods with fields

It's forbidden and with good reason I believe (it's not the same thing so it shouldn't be compatible), but you're right that it's possible to do so when directly manipulating the instance of the class. I don't know exactly why it is allowed, but we're not here to change how the language works so I believe we shouldn't interfere here.

About interfaces

Class interfaces describe the instance side of a class, meaning fields as well as methods from the prototype. I don't even think there's a difference between instance and prototype methods in an interface, I believe you can describe a method as one or the other, and implement it as one or the other. So implement could (and should) also apply to fields.

About new

new should have the same semantics as override does, so obviously you can't change the type to something that isn't compatible. I mean, again, we're not changing how the language works. I just wanted a separate keyword because it's not the same kind of redefinition. But, I agree that, as you showed me, we can already tell fields and methods apart by the use of =, so maybe the same keyword/syntax could be used were without ambiguity.

About this.

However, the unified field/method override syntax shouldn't be this.method() or this.field because it looks a lot like something that could be valid Javascript, while it's not. Adding a keyword before the member would be clearer towards the fact that is indeed a Typescript thing.
this is a fine idea though, so maybe we could drop the dot and write something less ambiguous like

class Superman {
    this walk() { }
}

But still, it looks a but weird. And mixing it with implement would look a bit out of place (because we're okay with the fact that this this syntax wouldn't be used with interface?), and I like the implement/override duo. An override modifier on fields still irks me, but maybe it is better that having a third ambiguous new keyword. Since the assignation (=) makes the difference between a method and a field clear, that would be fine by me now (as opposed to what I was saying a few hours ago).

JabX on 5 May 2016

I agree, fields can be reassigned, but so do methods on the prototype.

Yeah, modifying the prototype directly, in TypeScript, is very much in the realms off messing around under the hood though. It's nowhere near as common as simply re-assigning a property on an instance of something. We very rarely use fields as functions, over a 150k+ line codebase, so I think to say it's widely used is maybe subjective.

I agree with most of your other points, but I'm not sold (and by the sound of it, neither are you...) about the use of the new keyword in this context.

kungfusheep on 5 May 2016

We very rarely use fields as functions, over a 150k+ line codebase, so I think to say it's widely used is maybe subjective.

I don't either, but I have to resort to an @autobind decorator to properly bind this in my methods, which is more cumbersome than simply writing a lambda instead. And as long as you don't use inheritance, using a field works like you expect. I was under the impression that, at least in the JS/React world, most people using ES6 classes were using arrow functions as methods.

And interface methods can be implemented either with a proper method or with an instance method, which does not help with clarifying the difference.

I believe fields have the same problems as methods as far as overrides are concerned.

class A {
    firstName: string;
    get name() {
        return this.firstName;
    }
}

class B extends A {
    firstname = "Joe" // oops
}

A possible workaround here is to assign the field in the constructor

class B extends A {
    constructor() {
        this.firstName = "Joe"; // can't go wrong
    }
}

but that's not applicable for interfaces. That why I (and others here) believe we need something to check the pre-existence of a field when declaring it directly in the class body. And it's not an override. Now that I put some more thoughts here, I believe the issue with fields is exactly the same as the issue with interface members. I'd say we need an override keyword for methods that already have an implementation in a parent class (prototype methods, and maybe instance methods too), and another for things that are defined but without implementation (non-function fields included).

My new proposition would be, and using a tentative member keyword (probably not the best choice):

interface IBase {
    interfaceField?: string;
    interfaceMethod(): void
}

abstract class Base {
    baseField: number;
    baseMethod() { }
    baseLambda: () => { };
    abstract baseAbstractMethod();
}

class Derived extends Base implements IBase {
    member interfaceField = "Hello";
    member interfaceMethod() { }
    member baseField = 2;
    override baseMethod() { }
    override baseLambda = () => { };
    member baseAbstractMethod() { }
}

Note that I would choose the member keyword for an abstract method since I said override would be for things with an implementation, indicating that we're replacing an existing behavior. Instance methods would need to use override by virtue of being a special kind of field (which is already recognized as such by the compiler since method signatures can be implemented with it).

JabX on 5 May 2016

I think that Typescript should be a compile-time checked version of JavaScript, and by learning TS you should be learning JS as well, just as by learning C# you get a good intuition of the CLR.

Prototypal inheritance is a cool concept of JS, and a quite central one, and TS should not try to hide it with concepts from other languages that do not make too much sense here.

Prototypal inheritance doesn't make any difference if you're inheriting methods or fields.

For example:

class Rectangle {
       x: number;
       y: number;
       color: string;
}

Rectangle.prototype.color = "black";

Here we are setting a simple field in the prototype object, so all the rectangles will be black by default without having to have a instance field for it.

class BoundingBox {
      override color = "transparent"; // or should be member? 
}

Also the member keyword makes the other members in the class jealous.

What we need is a syntax that will allow in a class declaration context the same kind of behavior (compile time checked/auto-complete/renames) that we already have in object literal or member expressions.

Maybe a better alternative to this. is just .:

class Derived {
   .interfaceField = "hello";
   .interfaceMethod() {}
   .baseField = 2;
   .baseMethod() {}
   .baseLambda = () => {};
   .baseAbstractMethod(){};

   someNewMethod(){}
   someNewField = 3;
}

In conclussion, I don't think the the Typesystem shouod track which values come from the prototype and which from the instance, because this is a hard problem once you can access the prototype imperatively, and because is not going to fix any problem while will limit the expressivity of JS.

So there is no difference between a function field, and arrow function field and a method, nor in the type system, nor in the generated code (if this is not used).

olmobrutall on 6 May 2016

👍1

Hey guys, this is interesting stuff, but it's pretty out on a tangent in terms of override specifically. I'd be happy to have some new Discussion issue for this kind of thing to go in unless we can link these comments back to the original suggestion more concretely.

A lot of what you're saying here is really not specific to TypeScript, either, so starting an ESDiscuss thread may also be appropriate. Certainly they've thought about this sort of thing just as much (in terms of what goes on the prototype vs the instance).

RyanCavanaugh on 6 May 2016

👍3

@olmobrutall
ES6 classes are already hiding the prototype stuff, and like @kungfusheep said, messing directly with it isn't exactly a normal thing to do.

So there is no difference between a function field, and arrow function field and a method, nor in the type system, nor in the generated code (if this is not used).

Well, in the generated code, class methods are put in the prototype and everything else (not prefixed with static) in put in the instance, which does make a difference with inheritance.

Anyway, I now agree that we don't have to have a separate syntax for both kinds of methods, but if we were to use the override keyword, it should be limited to methods and we'd have to find something else for the rest. Having a unique keyword for everything could be nice but it should be very clear about its meaning. override is clear, but only for methods. You dot syntax, this like this. is still too close to existing JS to my taste.

JabX on 6 May 2016

👍1

@RyanCavanaugh

It's preatty out of tangent in terms of override

My issues with override is that is not general enough for interface methods and fields. I see three options:

use override just for base class methods.
use override for interface methods and fields as well
consider alternative syntaxes (member, implement, this. , ., etc...)
do nothing (that will be sad)

I think this decision should be taken here.

A lot of what you're saying is really not specific to Typescript

Absolutely! we are all happy about the current state for transpiling, but not on the type-checking / tooling.

Whatever the keyword is, it will be Typescript only (just as abstract)

olmobrutall on 6 May 2016

@JabX

You right about the generated code, of course. My point was that you can write something like this:

class Person {
    name: string = "John"; 

    saySomething() {
        return "Hi " + this.name;
    }
}

We declare a class, name will go to the instance while saySomething to the prototype. Still I can write this:

Person.prototype.name = "Unknown";

Because the type of Person.prototype is the whole person. Typescript doesn't keep track of what goes where on his type system for simplicity.

Having a unique keyword for everything could be nice but it should be very clear about its meaning.

What I think is more important and we all could agree is the semantics:

Modified XXX checks that the member is already declared in the base class or implemented interfaces, typically used to override functions from the base class.

Since . or this. look too alien, and member is redundant, I think probably the best choice is to abuse override for all the cases. Setting fields or implementing interface methods is anyway a side-feature.

There are many precedents:

In C# an static class is not really a _class of objects_ anymore.
There is nothing _static_ about static fields.
virtual methods are quite _concrete_ (VB uses Overrideable).

It will look like this:

class Person{
    dateOfBirth: Date;

    abstract talk();
    walk(){ //...}
}

interface ICanFly{
    fly?();
    altitude?: number;
}


class SuperMan extends Person implements ICanFly {
     override dateOfBirth = new Date();

     override talk(){/*...*/}
     override walk = () => {/* force 'this' to be captured*/} 

     override  fly() {/*...*/}
     override altitude = 1000; 
}

Can we settle on that?

olmobrutall on 6 May 2016

I'd rather see a separate implement keyword for anything that comes from interfaces (with priority to override if it's in both), because it's what it is: an implementation, not an override.
Otherwise, I agree it might be best to abuse override for everything from the parent class.

JabX on 6 May 2016

But there's no semantic difference between implement and override.

Both are going to have similar auto-complete / error messages / transpilation to JS... it's just a philosophical difference.

It's really worth to explain two keywords and that a pedanting compiler tells you: Error you should use 'override' instead of 'implement'.

What about a this case:

interface IComparable {
     compare(): number;
} 

class BaseClass implements IComparable {
    implement compare(); 
}

class ChildClass extends BaseClass implements IComparable { //again 
     override compare(); // or implements... 
}

The questions is... who cares?.

Also there is the implement/implements issue.

Let's just abuse override. One concept one keyword, this is the important thing.

olmobrutall on 6 May 2016

Well, I already proposed that override should have priority over implement, but I probably wasn't clear enough.
I still don't believe this is the same thing. Another example: for a mandatory interface member, a failure to implement is a compiler error whereas a failure to override is not an issue (unless the base member is abstract that is...).

I just don't think that override on something that isn't declared on a parent class would make any sense. But maybe I'm the only one who wants the distinction. In any case, whatever keyword we end up using for this, I just hope we can settle on something and provide a strict mode to enforce its use.

JabX on 6 May 2016

Well, I already proposed that override should have priority over implement, but I probably wasn't clear enough.

Sure, I just wanted to say that there are four cases. Base Class, Interface, Interface in Base Class, Re-implement Interface in BaseClass.

olmobrutall on 6 May 2016

@JabX

I just don't think that override on something that isn't declared on a parent class would make any sense. But maybe I'm the only one who wants the distinction.

You're not. They are two fundamentally different things and there is benefit in having that separation at language level.

I think if interfaces are to be supported in this new functionality then it cant be some half-baked solution that's been bolted onto override. For the same reason extends exists as a separate entity to implements at class level, override needs to be paired with something along the lines of implement in order to fix this problem. It's _replacing functionality_ vs _defining functionality_.

@olmobrutall

It's really worth to explain two keywords and that a pedanting compiler tells you: Error you should use 'override' instead of 'implement'.

I feel like I've made this distinction about 4 times now, but this isn't pedantic; it's really important information!

Consider your own example

interface IComparable {
     compare(): number;
} 

class BaseClass implements IComparable {
    implement compare(); 
}

class ChildClass extends BaseClass implements IComparable { //again 
     override compare(); // or implements... 
}

'or implements...' is a totally incorrect assumption to make in this case. Just because you've told the compiler you want to implement the same interface as the base class you're extending doesn't change the fact that you've already implemented compare.
If you were to write implement in ChildClass instead of override then you should be thankful that the compiler would then tell you of your incorrect assumption, because it's a big deal that you were about to unknowingly wipe out a previously implemented method!

In the codebases that I'm responsible for this would be a big problem without a doubt; so I welcome any compiler feature that can prevent any such developer mistakes!

kungfusheep on 7 May 2016

👍1

@kungfusheep

If you were to write implement in ChildClass instead of override then you should be thankful that the compiler would then tell you of your incorrect assumption, because it's a big deal that you were about to unknowingly wipe out a previously implemented method!

If overriding an already implemented method is such an important decision then implement should be used for abstract methods as well. If you change a method from abstract to virtual or the other way around you should check (and change) all the implemented versions to consider calling super or just removing the method.

In practice this has never been an issue in C#.

olmobrutall on 7 May 2016

I agree, override for implemented methods, and implements for unimplemented methods (abstract / interface).

eggers on 7 May 2016

It could be used for abstract, yes.

In C# there wasn't the 'optional' interface scenario, so perhaps wasn't deemed as much of an issue.

kungfusheep on 7 May 2016

But my point is that in C# we override implemented and unimplemented methods and I've never heard of someone complaining.

I don't think is really an issue that deserves making explaining the feature at least two times harder.

olmobrutall on 7 May 2016

Well, the only reason why we need an implement keyword is because interface members can be optional, whereas it's not possible in C# (and probably in most OO languages too). There is no keyword for that there because you cannot _not_ implement an interface completely, so no issue. Don't base your argument on "it's the same in C#" too much, because we have different problematics here.

override is used for _base class_ methods, whether they're abstract or not. I suppose we should to the same (override instead of implement for abstract methods) here because I believe the distinction should be on the origin of the method (class or interface) instead of on the existence of the implementation. And in the future, if you decide to give a default implementation to your abstract method, you won't have to go through your code (or worse, to the code of others using your class) to replace the keywords.

My main question now is, should we have a strict override/implement flag (I totally want this), should we force the implement keyword on mandatory interface members? Because it doesn't help a lot (you can't fail to implement these because otherwise it won't compile) and could lead to a lot of unnecessary verbosity. But on the other hand, it might be deceiving to have the implement on some interface members but not on all of them.

JabX on 7 May 2016

@JabX I would personally want a warning if a base class added an implementation of an abstract method.

However, I am not 100% sold on the idea of an implements keyword in the first place. The compiler will already warn you if you didn't implement something. The only place that it is really helpful is for optional methods.

And anyway, it has nothing to do with why I am in this thread. I was just looking if there was a way to specify a function as an override of a parent class.

eggers on 7 May 2016

My main question now is, should we have a strict override/implement flag (I totally want this), should we force the implement keyword on mandatory interface members?

I think not writing it should be a warning.

olmobrutall on 7 May 2016

The only place that it is really helpful is for optional methods.

Yeah, that's kind of the whole point here.

JabX on 8 May 2016

Without this it's very common error to typo method that you would like to override but in fact you are crating new method. Introduction of such keyword is only way to point out intention of overriding function.

That could be warning or whatever but currently it's very painful.

pankleks on 18 May 2016

❤1 👍1

I'm adding an override annotation to the UML class view in alm.tools :rose:

refs https://github.com/alm-tools/alm/issues/84

basarat on 20 May 2016

🎉1

I've also added a gutter indicator for class members that override a base class member in alm.

overrides

refs https://github.com/alm-tools/alm/issues/111

basarat on 26 May 2016

👍2

Accepting PRs for a scoped solution we think achieves the most value with the least complexity:

New keyword override is valid on class method and property declarations (including get/set)
- All signatures (including implementation) must have override if one does
- Both get and set must be marked override if either is
It is an error to have override if there's no base class property/method with this name
New commandline switch --noImplicitOverride (feel free bikeshed the name here) makes override mandatory for things that are overrides
- This switch has no effect in ambient contexts (i.e. declare class or .d.ts files)

Out of scope at this time:

Inheriting signatures
Contextual typing of parameters or initializers (tried this earlier and it was a disaster)
Corresponding keyword to indicate "I am implementing an interface member with this declaration"

RyanCavanaugh on 9 Jun 2016

👍15 ❤2

@RyanCavanaugh
I'm currently trying to implement this (just started, and I'd welcome any help on this, especially for testing), but I'm not sure I understand what's behind

All signatures (including implementation) must have override if one does

Since you can't have multiple signatures of a method in a class, are you talking about the inheritance context? Do you mean that (without the flag that enforces the use of override, otherwise it's obviously an error)

class A {
    method() {}
}

class B extends A {
    override method() {}
}

class C extends B {
    method() {} 
}

should output an error in class C because I didn't write override before method?

If that the case, I'm not sure why we'd want to enforce that. And should it also work the other way around? Output an error in class B if I specified the override in C and not in B?

JabX on 18 Jun 2016

👍1

Yes, I think it applies to the inheritance tree signatures.
And I don't think it will work the other way around, it should start enforcing the override rule once it's used at a level in the hierarchy. In some cases the decision to apply override may be made on a class derived from a class not owned by the developer. So, once it's used it should apply to all derived classes only.

joewood on 18 Jun 2016

I have another question about

Both get and set must be marked override if either is

What happens there if my parent class only defines a getter and I want to define in my derived class the setter? If I follow this rule, that means that my setter would have to be defined as an override, but there is no setter in the parent class, and it should be an error to override something that doesn't exist. Well, in practice (in my current naive implementation), there is no contradiction since the getter and the setter are for the same property.
I could even write something like:

class A {
    get value() { return 1; }
}

class B extends 1 {
   override set value(v: number) {}
}

Which looks plain wrong to me.

JabX on 19 Jun 2016

Since you can't have multiple signatures of a method in a class

You can have multiple overload signatures for the same method:

class Base { bar(): { } }

class Foo extends Base {
  // Must write 'override' on each signature
  override bar(s: string): void;
  override bar(s?: number): void;
  override bar(s: string|number) { }
}

I think your intuition about the other cases is correct.

Regarding getters and setters, I think override just applies to the property slot. Writing an overriding setter without a corresponding getter is clearly extremely suspicious, but it's no more or less suspicious in the presence of override. Since we don't always know how the base class was implemented, I think the rule is simply that an override getter or setter must have _some_ corresponding base class property, and that if you say override get {, any set declaration must also have override (and vice versa)

RyanCavanaugh on 20 Jun 2016

Oh ok I didn't know we could write method signatures in classes like that, that's pretty neat.

JabX on 20 Jun 2016

I think virtual would make sense too.
All keywords: virtual, override, final actually would make much difference especially when refactoring classes.
I'm using heavily inheritance, it's so easy now to override method "by mistake".
virtual would also improve intellisense, as you could propose only abstract/virtual methods after override keyword.

Please, please put priority on these. Thanks!

pankleks on 13 Aug 2016

👍6

I agree with @pankleks - I'm using inheritance a lot, and it just feels wrong to override a function without specifying anything directly.

"virtual", "override" and "final" would be perfect.

This is an important issue for me.

sam-s4s on 8 Sep 2016

👍2

@RyanCavanaugh

Contextual typing of parameters or initializers (tried this earlier and it was a disaster)

Can you elaborate on this? I actually found this issue while trying to find out why TS does not infer the type of my parameters on method overrides, which came as surprise to me. I don't see when a non-identical parameter list would be correct when overriding, or a return type which is not compatible.

@pankleks

I think virtual would make sense too.

By its nature everything is "virtual" in JS. Support for final would suffice IMHO: if you have a method (or property) which must not be overridden you could mark it as such to trigger a compiler error when this was violated. No need for virtual then, right? But this is tracked in issue #1534.

avonwyss on 9 Sep 2016

@avonwyss there are sort of two issues here.

When we tried contextually typing _property initializers_, we ran into some problems described at https://github.com/Microsoft/TypeScript/pull/6118#issuecomment-216595207 . We think we have a new more successful approach at #10570

Method declarations are a different ball of wax and there we have some other things to figure out, like what should happen here:

declare class Base {
  method(x: string): string[];
  method(x: number, count: number): number[];
}
class Derived extends Base {
  method(x) { // x: ???
    return x;
  }
}

We may just decide that only single-signature methods get parameter types from the base. But this isn't going to make everyone happy and doesn't really solve the frequent problem of "I want my derived class to method have the same _signatures_ but just provide a different _implementation_".

RyanCavanaugh on 9 Sep 2016

Well, x's type would be string | number in that case, but I understand that it might be pretty hard to find out consistently.

JabX on 9 Sep 2016

But you probably wouldn't want the _externally-seen_ type of x to be string | number - assuming Derived has the same semantics as Base, it wouldn't be legal to invoke with (3) or ('foo', 3)

RyanCavanaugh on 9 Sep 2016

👍1

Hum yeah, I missed that.

I see you suggested to restrict it to single-signature methods, but I believe it could be "easily" expanded to "matching-signature" methods, like in your exemple:

declare class Base {
  method(x: string): string[];
  method(x: number, count: number): number[];
}
class Derived extends Base {
  method(x, count) { // x: number, count: number
    return [];
  }
}

because there is only on signature on the base class that matches.

That would be way better than what we have (nothing), and I don't think it would be _that_ hard to do? (still way out of scope for this issue and probably more work)

JabX on 9 Sep 2016

@RyanCavanaugh Thanks for the reply. As noted my hope for override is that it would sort the parameter (and return type) issue out. But I don't see your example as problematic, since overloads always have to have one single "private" implementation which is compatible with all overloads (which is why the suggestion from @JabX would not work conceptually).
So, we'd have something like this:

declare class Base {
  method(x: string): string[];
  method(x: number, count: number): number[];
  // implies: method(x: string|number, count?: number): string[]|number[]
  // or fancier: method<T extends string|number>(x: T, count?: number): T[]
}
class Derived extends Base {
  override method(x, count?) { // may only be called like the method on Base
    return [x];
  }
}

This logic already exists and the override would obviously only be available for the "private" implementation method, not the distinct overrides (just as you cannot explicitly implement a single overload anyways). So I do not see a problem here - or did I miss something?

Methods designed to be overridden usually don't have overloads anyways, so even taking the simple way out and not infer the parameter and return types if overloads exist would be perfectly fine and useful. So even if the behavior was as-is when overriding overloaded methods, you'd get an error when running in --no-implicit-any mode and you'd have to specify compatible types, that would seem like a perfectly fine approach.

avonwyss on 10 Sep 2016

I'm probably missing something, but in Javascript (and thus Typescript) you cannot have 2 methods with the same name - even if they have different signatures?

In C#, you could have

public string method(string blah) {};
public int method(int blah) {};

But here you can never have 2 functions with the same name, no matter what you do with the signatures... so none of your examples would ever be possible anyway, right? Unless we're talking about multiple extends on the same class... but that is not what your examples are showing, so probably not? Is this a non-issue?

Right now I'm using inheritance, and it is very frustrating... I'm having to put comments about functions to indicate that they're virtual (ie. I'm overriding them somewhere) or override (ie. that this function is overriding an underlying function). Super annoying and messy! And unsafe!

sam-s4s on 12 Sep 2016

@sam-s4s Yes it is possible to declare multiple logical overload signatures for a method, but they all end up on the same single implementation (which then has to figure out by the passed parameters which "overload" is being called). This is heavily used by many JS frameworks, for instance jQuery where $(function) adds a ready function, but $(string) searches the DOM by selector.

See here for the docs: https://www.typescriptlang.org/docs/handbook/functions.html#overloads

avonwyss on 12 Sep 2016

@avonwyss Ah yes, declarations, but not implementations, that makes sense :) Thank you

sam-s4s on 12 Sep 2016

This has gone on waaay too long, and i find it annoying that I have to read this entire bloated thread to even begin to figure out why TS still does not have this basic compile-time assertion.

Where are we on either (a) an override keyword or (b) an @override jsdoc annotation that informs the compiler "a method having the same name and type signature MUST exist on a superclass."?

More specifically, does the comment in https://github.com/Microsoft/TypeScript/issues/2000#issuecomment-224776519 (Jun 8 2016) by @RyanCavanaugh suggest that the next step is a (community) PR?

class Bar extends Foo {
  /**
   * @override
   */
  public toString(): string {
     // ... 
  }

  override public toString(): string {
    // ...
  }
}

pcj on 28 Dec 2016

More specifically, does the comment in #2000 (comment) (Jun 8 2016) by @RyanCavanaugh suggest that the next step is a (community) PR?

@pcj Correct

RyanCavanaugh on 28 Dec 2016

I've started a PR on this at #13217. Anyone else interested in this functionality is most welcome to participate and/or provide suggestions. Thanks!

pcj on 29 Dec 2016

👍11

I would prefer the same as for java with a decorator

@Override
public toString(): string {
   // ...
}

Chris2011 on 3 Feb 2017

👎22 👍4

@Chris2011 Agree this looks familiar, but this would imply as a decorator that @Override would be evaluated at runtime, not compile-time. I am planning javadoc /** @override */ in a separate PR once #13217 override keyword (public override toString()) moves forward in review.

pcj on 3 Feb 2017

👍4

Trying to follow the conversation of this thread. Does this include static functions? I don't see any reason why we couldn't also allow overriding static functions in derived classes with completely different signatures. This is supported in ES6. If had class A { } ; A.create = function (){} then class B extends A { } ; B.create = function (x,y) { }, calling A.create() is not going to call B.create() and cause issues. For this reason (and to create the ability to use the same function name on types as factory functions) you should also allow override the signature of base static functions. It's doesn't break anything, and adds the ability to do some neat stuff (especially for game engine frameworks, where 'new' anything is really an evil if used all the time without pulling from a cache of objects to reduce GC freezes). Since callable constructors are not supported under ES6, creating a common naming convention for methods on types is the only other option; however, doing so currently requires the derived static function to show an overload of the base static function signature along with it's own, which is not useful for a factory function on a type that only deals with THAT type. :/ In the mean time the only option I have is to force users of my framework to duplicate all base hierarchy static function signatures (such as SomeType.create()) on their derived types, and so on, which just gets really silly.

rjamesnw on 1 May 2017

Here is an example about the "silliness" I'm talking about (which works, but not something I'd be proud of in an extensible framework):

class A {
    static create(s: string) {
        var inst: A;
        /* new or from cache */
        inst.init(s);
    }
    protected init(s: string) { }
}

class B extends A {
    static create(s: string);
    static create(n: number);
    static create(n:any) {
        var inst: B;
        /* new or from cache */
        inst.init(n);
    }
    protected init(s: string);
    protected init(n: number);
    protected init(n: any) {
        super.init(n.toString());
    }
}

class C extends B {
    static create(s: string)
    static create(n: number)
    static create(b: boolean)
    static create(b: any) {
        var inst: C;
        /* new or from cache */
        inst.init(b);
    }
    protected init(s: string);
    protected init(n: number);
    protected init(b: boolean);
    protected  init(b: any) {
        super.init(b ? 0 : 1);
    }
}

(https://goo.gl/G01Aku)

This would have been much nicer:

class A {
    static create(s: string) {
        var inst: A;
        /* new or from cache */
        inst.init(s);
    }
    protected init(s: string) { }
}

class B extends A {
    new static create(n:number) {
        var inst: B;
        /* new or from cache */
        inst.init(n);
    }
    new protected init(n: number) {
        super.init(n.toString());
    }
}

class C extends B {
    new static create(b: boolean) {
        var inst: C;
        /* new or from cache */
        inst.init(b);
    }
    new protected  init(b: boolean) {
        super.init(b ? 0 : 1);
    }
}

rjamesnw on 1 May 2017

@rjamesnw you may be interested in Polymorphic "this" for static members having a contract for factory functions is discussed as a primary use case throughout the comments.

aluanhaddad on 29 Jul 2017

so, again restating a feeling that @pcj expressed (comment) over a year ago, it's confusing to have to read so many PRs and comments here and elsewhere to determine where this feature request is at.

it seems like #13217 was so close, then shot down again by @DanielRosenwasser and company as a feature that may not fit the language, seemingly re-entering the circular conversation here on this issue about whether or not it should be done. Maybe this 'design-time' decorators (#2900) thing will solve it, maybe not? It'd be nice to know.

ekilah on 4 Apr 2018

👍6

Here's a few more shortcomings of the runtime decorator approach posted a few years ago that I didn't see mentioned:

It won't work with properties since they're not part of the prototype
Properties and accessors can (sort-of...) override one another, which also won't work
We have abstract classes now, but since abstract things don't actually exist at runtime, it can't possibly work with them

If the only caveat was that the checks occurred upon class initialisation then I could probably accept it as a temporary measure, but as is there are just too many limitations.

rosslovas on 16 May 2018

👍2

Frankly I cannot believe this feature is still so controversial over 3 years since I first logged the issue. Every "serious" object oriented language supports this keyword, C#, F#, C++... you name it.

You can argue hypotheticals all day long about why javascript is different and needs a different approach. But from a practical perspective working daily in a very large Typescript code base, I can tell you that override would make a huge difference to code readability and maintenance. It would also eliminate an entire class of bugs due to derived classes accidentally overriding base class methods with compatible but subtly different signatures.

rwyborn on 16 May 2018

👍23

I would really love to see a proper implementation of virtual / override / final. I'd be using it all the time, and it would make code so much more readable and less error-prone. I feel like this is an important feature.

sam-s4s on 16 May 2018

👍17

Agreed. It's frustrating to see how relatively obscure / edge-case features are being added, while something so... fundamental is being rejected. Is there anything we can do to push for this?

armandn on 16 May 2018

👍30

Come on people! If there is this many comments and over three years, why isn't it implemented already!

sssalib42 on 12 Jun 2018

👍13

Come on :joy_cat:

liuchong on 22 Jun 2018

👍6 👎1

Please be constructive and specific; we do not need dozens of PLEASE DO IT ALREADY comments

RyanCavanaugh on 26 Jun 2018

👍14 😄1

But guys, please be specific also on your side.

Obviously community is very interested in that feature, and TS team does not give us any specifics about future of this one.

I personally completely agree with @armandn , recent releases of TS brings relatively rarely used features while something like this is being held.

If you don't plan to do it, just tell us. Else please let us know how community can help.

pankleks on 27 Jun 2018

👍7

https://github.com/Microsoft/TypeScript/pull/24626 too.

falsandtru on 27 Jun 2018

Just a timeline here since there are more comments than GitHub is willing to display on load:

The initial issue was opened
We reviewed it and declined it on complexity vs value grounds https://github.com/Microsoft/TypeScript/issues/2000#issuecomment-98874744
We reopened it after #6118 failed to work https://github.com/Microsoft/TypeScript/issues/2000#issuecomment-216626012
We said we'd accept a PR after making some decisions https://github.com/Microsoft/TypeScript/issues/2000#issuecomment-224776519
PR got opened at #13217
After extensive review of the PR (nearly 100 comments) we took it back to the design meeting due to complexity concerns #20724
Again, we decided that the benefits of the feature did not outweigh complexity

It's not like we're not taking consideration here. This is as close as features get to going in, and we've rejected our own feature ideas on similar grounds - see #24423 for a recent example.

We really want to grow the language intentionally. This takes time, and you should expect to have to be patient. By comparison, C++ is older than a lot of people in this thread; TypeScript is not yet old enough to be at home without adult supervision. Once we add something to the language, we can't take it out again, so every addition has to be carefully weighed against its pros and cons. I speak from experience that features people were SCREAMING for (extension methods, I'm looking at you) would have destroyed our ability to continue evolving the language (no intersection types, no union types, no conditional types) had we implemented them just because there were lots of GitHub comments. I'm not saying override is a dangerous thing to add, just that we are always approaching this with the absolute maximum of caution.

If I had to summarize the core problems with override right now:

It doesn't let you do anything that you can't do today with a decorator (so it's "not new" in terms of "things you can accomplish")
The semantics cant't precisely align with override in other languages (increases cognitive load)
It doesn't "light up" 100% without a new commandline flag, and it'd be a flag we'd probably want to be under strict but realistically couldn't because it'd be too big of a breaking change (decreases delivered value). And anything that implies a new commandline flag is another doubling of the configuration space that we need to weigh seriously, because you can only double something so many times before it consumes your entire mental budget when making future decisions
Fairly strong internal disagreement here about whether override can apply to implementing an interface member (decreases perceived value because expectations won't match reality for some proportion of people)

The total upside here is that you can a) indicate that you're overriding something (which you could do today with a comment), b) catch a misspelling that autocomplete should have helped you with anyway, and c) with a new flag, catch places where you "forgot" to put a keyword and now need to (a plain mechanical task that is unlikely to find real bugs). I get that b) is extremely frustrating but again, we need to meet the complexity bar here.

At the end of the day if you think JS classes would be enormously helped by an override keyword, then championing a TC39 proposal to add it to the core runtime would be a good place to start.

RyanCavanaugh on 27 Jun 2018

👍24 🎉4 ❤3 👀1 😄1 👎1

It doesn't let you do anything that you can't do today with a decorator (so it's "not new" in terms of "things you can accomplish")

Maybe I'm misunderstanding this, but there are pretty important things that a decorator can't do which the keyword could. I mentioned some in https://github.com/Microsoft/TypeScript/issues/2000#issuecomment-389393397. Definitely correct me if those things are possible, because I would like to use the decorator approach but non-abstract methods are only a small part of my use case for this feature.

Another upside not mentioned is that an override keyword would make changing something in a base class a lot more feasible. Changing a name or splitting something into two parts etc. is difficult knowing that any deriving classes will compile just fine without being updated to match but will probably fail at runtime. Also, considering that there's no final/sealed/internal keywords available, just about any exported class might be derived somewhere making changing just about anything non-private a lot riskier than it would be with override available.

rosslovas on 28 Jun 2018

👍3

My impression is that a TSLint rule would be by far the smoothest path forward here. @kungfusheep briefly mentioned the idea in https://github.com/Microsoft/TypeScript/issues/2000#issuecomment-192502734 , but I don't see any follow-up. Is anyone else aware of a TSLint implementation of this feature? If not, I'll probably start hacking on one when I get a chance. 😄

My current thought is it'll just be a comment, // @override, just like // @ts-ignore and various other comment-based directives I've seen. I'd personally prefer to shy away from decorators since (in their current form) they have runtime semantics and since they're still stage 2 and disabled by default.

With any luck, a custom TSLint rule would be a 90% solution, only really lacking in aesthetics, and of course it could move forward without having to commit to any details of the language. With type-aware rules, tslint-language-service, and auto-fixing, there's really not much difference between a TSLint error and a built-in TS error from the developer's perspective. My hope is that a TSLint plugin (or multiple competing plugins) would give the community some experience and a chance to come to more of an agreement on the best semantics. Then maybe it could get added as a core TSLint rule, and maybe that would provide enough clarity and motivation to justify the aesthetic benefit of an override keyword in the core language.

alangpierce on 28 Jun 2018

👍3 🚀1

Just thinking outside the box here. We have two different scenarios here. C# (just as an example) uses virtual and override because methods are NOT virtual by default. In JavaScript all functions on a class are virtual by default (by nature). Does it not make more sense then to invert the process and have a nooverride type modifier instead? Of course people could still force it, but at least it’s there to help push a convention that some functions in base classes should not be touched. Again, just thinking outside the norm here. ;) It may also be less of a breaking change.

rjamesnw on 28 Jun 2018

Does it not make more sense then to invert the process and have a nooverride type modifier instead?

I like your way of thinking, and I think what you are looking for is final.

What about readonly though? I believe overriding a method in JS actually means replacing the parent's with the child's during instantiation (when the prototype chain gets applied). In that case, having a readonly method to mean "It's there for everyone to see, but I don't want anyone to change it, whether by inheritance or dynamically after instantiation" makes a lot of sense. It's already implemented for members, why not do it for methods as well?

Is there already a proposal for it? If not it could be worth investigating as an alternative to override...

_edit:_ turns out you can override a readonly member, so this whole argument collapses.

hmil on 28 Jun 2018

Perhaps allowing private class functions is another option?

Edit: I was thinking "instead of marking it final" but I must have been half asleep (obviously "final" means public but cannot override), LOL; nevermind.

rjamesnw on 28 Jun 2018

😕1 😄1 👎1

@rjamesnw you can already define class functions as public, protected, private.

I don't think that only having "final" would be a solution. The problem is that people can accidentally create a new function in a class that inherits from a base class with that name already in use, and then you'll be breaking things silently without knowing why. It's happened to me a few times, very frustrating, as you often don't get errors, and strange things just happen (or don't)...

So I think, really, we're looking at a new tsconfig.json entry that will force the compiler to throw an error when something is overridden without it being marked as virtual (and the overriding one being marked as override or final).

sam-s4s on 1 Jul 2018

I think that without override, TypeScript is disappointing its users on its [perceived] promise of compile-time safety and type-safety.
The "use an IDE command to override method" argument breaks down as the code is evolving (as other people have pointed out).
Also looks like all major comparable languages have added override in some form.
To not make it a breaking change, it could be a tslint rule (similarly as in Java).
Btw, why not allow breaking changes between major versions language e.g. 2.x -> 3.x. We don't want to get stuck, do we?
If it turns out something is wrong with certain details of override, and it requires some breaking-change-tweaking in 3.x, so be it. I think most people will understand and appreciate the tradeoff of evolution speed vs compatibility. Really without override I cannot recommend TS as something more practical than Java or C#...

If people want to be strict, there should be some way of mandatory override (could be an optional tslint rule). The value of mandatory override though is much lower, because chance of accidentally overriding a method from superclass seems much much lower than accidentally not-overriding.

Really this issue being open since 2015 is a bucket of cold water on my TypeScript enthusiasm and evangelism...

karol-depka on 4 Jul 2018

This does not handle overriding methods from grand*-parents:

/* Put this in a helper library somewhere */ function override(container, key, other1) { var baseType = Object.getPrototypeOf(container); if(typeof baseType[key] !== 'function') { throw new Error('Method ' + key + ' of ' + container.constructor.name + ' does not override any base class method'); } }

karol-depka on 4 Jul 2018

It is also sad and disappointing that No one assigned on GH here on this issue. Maybe time for a TypeScript fork? ;) CompileTimeSafeScript...

karol-depka on 4 Jul 2018

😄4

This whole thread looks like a big "Paralysis by analysis" anti-pattern. Why not just do the "80% cases value with 20% of work" and, try it in practice, and, if necessary, tweak it in 3.x ?

The simple, frequent and very valuable use cases are held "hostage" by some corner cases that most people will never really need to worry about.

karol-depka on 4 Jul 2018

👍3

So, this is possible to type-check at compile time via decorators, albeit not without a little bit of help:

export const override = <P extends Function>() => <K extends keyof P["prototype"]>(
  target: Object,
  methodName: K,
  descriptor: TypedPropertyDescriptor<P["prototype"][K]>
) => {
  // this is a no-op. The checking is all performed at compile-time, so runtime checks are not needed.
}

class Bar {
  biz (): boolean {
    return true;
  }

  qux (): string {
    return "hi";
  }
}

class Foo extends Bar {
  // this is fine
  @override<typeof Bar>()
  biz (): boolean {
    return false;
  }

  // error: type '() => number' is not assignable to type '() => boolean'
  @override<typeof Bar>()
  biz (): number {
    return 5;
  }

  // error: argument of type '"baz"' is not assignable to parameter of type '"biz" | "qux"'
  @override<typeof Bar>()
  baz (): boolean {
    return false;
  }
}

I'm not sure if it's possible to get a reference to the super type without passing it in explicitly. This incurs a tiny runtime cost, but the checking is all compile time.

bioball on 4 Jul 2018

👍3

@alangpierce

My impression is that a TSLint rule would be by far the smoothest path forward here.

[...]

Then maybe it could get added as a core TSLint rule, and maybe that would provide enough clarity and motivation to justify the aesthetic benefit of an override keyword in the core language.

100% agreed. Let's get started already!

hmil on 6 Jul 2018

👍3 🎉1

Hi - a little later than planned but here is our tslint rule implemented using a decorator.

https://github.com/bet365/override-linting-rule

We have been using this across our ~1mloc TypeScript codebase for a couple of years and have recently updated it to use the language service, making it much faster to execute and more feasible to open source (the previous iteration required a full pass of the project to gather the heritage information).

For our use-case it has been invaluable - though we're still of the opinion that the responsibility should ultimately lie with the compiler and as such the linting rule should be seen as a stop-gap.

Thanks

kungfusheep on 6 Jul 2018

👍11 🎉2 ❤1

I agree. I also believe that a solution involving the TS compiler would be much better than decorators and lint rules.

sam-s4s on 9 Jul 2018

👍5

What is the status of this feature? Has it been revisited as a compiler-feature yet?

FeaturedSpace on 2 May 2019

👍21

So, this is possible to type-check at compile time via decorators, albeit not without a little bit of help:

Some improvements:

function override< Sup >( sup : { prototype : Sup } ) {
    return <
        Field extends keyof Sup ,
        Proto extends { [ key in Field ] : Sup[ Field ] } ,
    >(
        proto : Proto ,
        field : Field ,
        descr : TypedPropertyDescriptor< Sup[ Field ] > ,
    )=> {}
}

class Foo {

    bar( a : number ) {
        return a 
    }

    bar2( a : number , b : number ) {
        return a 
    }

}

class Foo2 {

    @override( Foo )
    bar( a : number ) {
        return 1
    }

    @override( Foo )
    bar2( a : number , b : number ) {
        return 1 
    }

    xxx() { return '777' }

}

class Foo3 extends Foo2 {

    @override( Foo ) // OK
    bar( a : number ) { return 5 }

    @override( Foo ) // Error: less args than should
    bar2( a : number ) { return 5 }

    @override( Foo ) // Error: accidental override Foo2
    xxx() { return '666' }

    @override( Foo ) // Error: override of absent method
    yyy() { return 0 }

}

Playground

nin-jin on 12 Aug 2019

👍8

Ok, found out override solution that prevents compilation error.
Example with Node Readable stream:

// Interface so you will keep typings for all Readable methods/properties that are not overriden:
// Fileds that are `Omit`-ed should be overriden (with any signature you want, it do not have to be compatible with parent class)
interface ReadableObjStream<T> extends Omit<stream.Readable, 'push' | 'read'> {}

// Use extends (TYPE as any) to avoid compilation errors and override `Omit`-ted methods
class ReadableObjStream<T> extends (stream.Readable as any) {
    constructor()  {
        super({objectMode: true}); // force object mode. You can merge it with original options
    }
    // Override `Omit`-ed methods with YOUR CUSTOM SIGNATURE (can be non-comatible with parent):
    push(myOwnNonCompatibleSignature: T): string  { /* implementation*/ };
    read(options_nonCompatibleSignature: {opts: keyof T} ): string  { /* implementation*/ }
}

let typedReadable = new ReadableObjMode<{myData: string}>();
typedReadable.push({something: 'else'}); // will throw compilation error as expected
typedReadable.pipe(...) // non overloaded methods typings supported as expected

The only disadvantage of this solution is lack of typings when calling super.parentMethod (but thanks to the interface ReadableObjStream you have all the typings when using instance of ReadableObjStream.

fider on 28 Oct 2019

@nin-jin @bioball Thanks for the contributions with the decorator compile-time checking.

Unfortunately it doesn't seem to work with protected members, only with public.

(example of error in my fork of nin-jin's playground

uglycoyote on 13 Nov 2019

👍1

The override specifier was a killer feature in c++ 11.
It so much helps and protects refactoring code.
I definitely would like to have this in TS base support without any hurdles (VOTE!)

JanFellner on 11 Dec 2019

👍11 ❤1

We've definitely shown wild support for this feature, but it seems they still don't plan on adding this feature anytime soon.

FeaturedSpace on 13 Dec 2019

Another idea:

class Obj { 

    static override<
        This extends typeof Obj,
        Over extends keyof InstanceType<This> = never,
    >(this: This, ...overs: Over[]) { 
        return this as This & (
            new(...a:any[])=> InstanceType<This> & Protect< Omit<InstanceType<This> , Over > >
        )
    }

}

class Foo extends Obj {

    bar(a: number) {
        return 0
    }

    bar2(a: number) {
        return 0
    }

    foo = 1

}

class Foo2 extends Foo.override('bar') {

    foo = 2

    bar( a : number ) {
        return 1
    }

    // Error: Class 'Foo & Protect<Pick<Foo, "bar2" | "foo">>'
    // defines instance member property 'bar2',
    // but extended class 'Foo2' defines it as instance member function.
    bar2( a : number ) {
        return 1
    }

    bar3( a : number ) {
        return 1
    }

}

declare const Protected: unique symbol

type Protect<Obj> = {
    [Field in keyof Obj]:
    Object extends () => any
    ? Obj[Field] & { [Protected]: true }
    : Obj[Field]
}

Playground Link

nin-jin on 31 Mar 2020

👍3

Adding my two cents here.
We have a typical angular component, that handles forms and needs to unsubscribe from valueChanges and such. We didn't want to repeat the code all over the place (kinda current state), so I've made a "TypicalFormBaseComponent" that (among other things) implements angulars OnInit and OnDestroy methods. The issue is that now if you actually use it and add your own OnDestroy method (which is pretty standard thing to do), you hide the original one and break the system. calling super.OnInit fixes it, but there is currently no mechanism for me to force the children to do that.

If you do it with the constructor, it forces you to call super()... I was looking for something similar, found this thread, and honestly, I am kinda bummed.
Implementing "new" and "override" in the ts might be a breaking change, but fixing it would be incredibly simple in basically any codebase (just adding 'override' everywhere where it screams). It might also be just a warning.

Anyways, is there some other way for me to force the super call in the children? TSLint rule that prevents hiding, or something like that?

PS: I don't agree with the "no comment" policy. It prevents people from throwing examples here. Maybe you won't implement 'override', but you'll implement something else, that takes care of their problems... that is, if you can actually read them.

GonziHere on 28 May 2020

👀3

@GonziHere In other languages such as C# or Java, overriding does not imply the requirement to call the super method - it often is not the case in fact. Constructors are special and not normal "virtual methods".

The override keyword would be used to specify that the method must already be defined with a compatible signature on the base class, and the compiler could assert this.

avonwyss on 28 May 2020

👍4

Yes, but the need for override forces you to notice that the method exists.

GonziHere on 28 May 2020

👍6

@GonziHere Look like what you may really need is to create abstract base classes with abstract functions. Perhaps you can create private _onInit and _onDestroy methods you can more rely on, then create protected onInit and onDestroy abstract functions (or regular functions if they are not requried). The private functions will call the others, then complete as normal.

rjamesnw on 28 May 2020

@GonziHere @rjamesnw The safe thing to do is actually to somehow enforce that onInit and onDestroy are _final_, and define empty protected abstract template methods that the final methods call. This guarantees that nobody can accidentally override the methods, and trying to do so (assuming there were a way to enforce final methods) would immediately point users to the right way to implement what they want.

shicks on 11 Sep 2020

👍1

@shicks, @rjamesnw, I'm in the same situation as @GonziHere. I don't want the base class to have abstract methods because there is functionality that I want executed for each of those lifecycle hooks. The problem is that I don't want that base functionality to be accidentally replaced when someone adds ngOnInit or ngOnDestroy on the child class without calling super(). Requiring override would bring to the attention of the dev that those methods exist in the base class and that they should choose if they need to call super();

aeslinger0 on 23 Sep 2020

👍5

From my experience writing Java, @Override is so common that it becomes noise. In many cases, the overridden method is abstract or empty (where super() should _not_ be called), making the presence of override not a particularly clear signal that super() is needed.

shicks on 23 Sep 2020

👎8

From my experience writing Java, @Override is so common that it becomes noise. In many cases, the overridden method is abstract or empty (where super() should _not_ be called), making the presence of override not a particularly clear signal that super() is needed.

That has nothing to do with the subject at hand. You might just as well said to use composition over inheritance to avoid the problem.

aipirvu on 24 Sep 2020

👍11

For me, the most useful part of override is to get an error while refactoring.
Right now it is all too easy to rename some method in a base class and forget to rename the ones that override it.
Remembering to call super is not that important. It is even correct to not call it in some cases.

lorenzodallavecchia on 24 Sep 2020

👍16

I think that there is a misunderstanding on why the _override_ would be important. Not to force someone to call the _super()_ method, but to make them aware that one exists and allow them to conscientiously decide whether they want to suppress its behavior or extend it.

aipirvu on 24 Sep 2020

👍13

The pattern I use to ensure correctness is to use Parameters and ReturnType while referring very explicitly to the base class, something like this:

class Base {
    public methodName(arg1: string, arg2: number): boolean {
        return false; // base behaviour, may be stub.
    }
}
class Derived extends Base {
    public methodName(...args: Parameters<Base["methodName"]>): ReturnType<Base["methodName"]> {
        const [meaningful, variableNames] = args;
        return true; // implemented behaviour here.
    }
}

This kind of pattern is the basis for my suggestion to add an inherit keyword.. This ensures that any updates to the base class automatically propagate and if invalid in the derived class then an error is given, or of the name changes of the base class then an error is also given, also with the inherit idea you aren't constrained to only offer identical signature to the base class but can intuitively extend it.

tadhgmister on 24 Sep 2020

👍1

I also think there's a misunderstanding about why override would be important, but I don't really understand all these issues with "whether super() is needed".

To echo what @lorenzodallavecchia and the original author of the issue have said, marking a function as override is a mechanism to avoid screw-ups that happen when the superclass is refactored, specifically when the name and/or signature of the overridden function changes or the function is removed.

Keep in mind that the person changing the signature of the overridden function may not be aware that overrides exist. If (e.g. in C++) the overrides are not explicitly marked as overrides, then changing the name/signature of the overridden function does not introduce a compilation error, it simply causes those overrides to no longer be overrides. (and.. probably no longer be useful, no longer be called by code that used to call them, and introduce a bunch of new bugs because things that are supposed to call the overrides are now calling the base implementation)

The override keyword, as implemented in C++, saves the person changing the base implementation from these problems, because immediately after their refactoring, compilation errors will indicate to them that a bunch of overrides exist (that override a now-nonexistent base implementation) and clue them in to the fact that they probably need to refactor the overrides as well.

There are secondary IDE usability benefits to having the override modifier as well (also mentioned by original author), namely that upon typing the word override the IDE can helpfully show you a bunch of possibilities of what can be overridden.

uglycoyote on 25 Sep 2020

👍14

Together with the override keyword it would be good to also introduce a flag that, when enabled, requires that all methods that override another uses the override keyword, so as to avoid cases where you create a method in a subclass and in the future the base class (that could be in a 3rd party library) creates a method with the same name as the method you created in the subclass (which could cause bugs now, because the subclass had overridden that method).

Getting a compilation error in this case, saying that you need to add the override keyword in this method (even tough you may not actually override the method, just change its name so as to not override the newly created method in the base class), would be much better and avoid possible runtime bugs.

lucasbasquerotto on 25 Sep 2020

👍11 👎1

From my experience writing Java, @Override is so common that it becomes noise.

After many Java-years I strongly disagree with above statement. Override is a way of communication, like checked exceptions. It's not about like or dislike, but about quality and expectations.

And therefore a big +1 to @lucasbasquerotto , but from another point of view: if I introduce a method in a subclass I want to have a clear semantic of overriding or not overriding. For example if I want to override a method, then I want to have a way to tell that explicitly. If something wrong with my implementation, for example a typo or wrong copy&paste, then I want to get feedback about it. Or other way: if I don't expect to override, I want feedback too, if overriding occasionally happens.

Bessonov on 25 Sep 2020

👍10

Feedback from another Java developer... @override is the only feature I'm really missing from Typescript.

I have ~15 of Java experience and 1-2 years or Typescript so pretty comfortable with both.

The zen of @override is you can remove a method from an interface and the compilation will break.

It's like the reverse of tight binding for new methods. It allows you to remove old ones.

If you implement an interface and ADD a method the compilation will fail but there isn't an inverse of this.

If you remove a method you'll just end up with dead code.

(though maybe that can be fixed by a linter)

burtonator on 6 Nov 2020

👍1

To be clear, when I said that @Override was noise, I was specifically referring to the comment about it being a signal that you need to call super. The checking it provides is valuable, but for any given overridden method, it's a complete toss-up whether it's required or pointless to call super. Since such a large fraction of overridden methods _shouldn't_, it's ineffective for that purpose.

My entire point is that if you want to ensure subclasses call back into your overrideable methods, the only effective way to do that is to make the method final (see #33446, among others) and have it call into a _differently-named_ empty template method that can be safely overridden _without_ the super call. There's simply no other reasonable way to get that invariant. I'm completely in favor of override, but as someone who's been burned by users incorrectly subclassing my APIs (and I'm on the hook not to break them), I believe it's worth shifting attention to final as the correct solution to this issue, rather than override as was suggested upthread.

shicks on 7 Nov 2020

I'm a little confused as to why people keeps suggesting one of final or override over the other. Surely we want both, as they solve different problems.

Override
Prevents people who are extending a class from accidentally overwriting a function with their own, breaking things in the process without even knowing. Having an override keyword lets the developer know that they are in fact overriding an existing function, and then they can choose to either rename their function or use the override (and then they can find out if they need to call super).

Final
Prevent people who are extending a class from overwriting a function completely, so that the original creator of the class can guarantee complete control.

sam-s4s on 9 Nov 2020

👍15

@sam-s4s We want the define too :-)

Example of issue..

Initial

class Base {}
class Entity extends Base {
    id() {
        return 'BUG-123' // busisess entity id
    }
}

Base class refactored

class Base {
    id() {
        return '84256635572' // storage object id
    }
}
class Entity extends Base {
    id() {
        return '12' // busisess entity id
    }
}

We got accidental overload here.

Case with `define` keyword

class Base {
    define id() {
        return '84256635572' // storage object id
    }
}
class Entity extends Base {
    define id() {
        return '12' // busisess entity id
    }
}

Shold be error: Accidental redefine. Use override keyword to override base class method.

Workaround with decorators

nin-jin on 10 Nov 2020

@nin-jin isn't define the same as _not_ using override?

lorenzodallavecchia on 10 Nov 2020

@sam-s4s We want the define too :-)

Oh, I've not seen anyone here mention a keyword define - but from what you describe, I assume you mean like the word virtual in C# ?

(also I found you example a little confusing, as your classes Base and Entity are not related. Did you mean for Entity to extend Base?)

I guess there are 2 scenarios...
a) you write your base class, assuming everything without final can be overridden.
b) you write your base class assuming everything without virtual cannot be overridden.

sam-s4s on 10 Nov 2020

@sam-s4s Entity extends Base, of course. :-) I have fixed my message. virtual is about something else.
@lorenzodallavecchia not using override is define | override for compiler. Using define is only define and compiler can strict check this.

nin-jin on 11 Nov 2020

@nin-jin In your model, this means not using the override keyword is still legal, right? For instance:

class Base {
  myMethod () { ... }
}

class Overridden extends Base {
  // this would not fail because this is interpreted as define | override.
  myMethod () { ... }
}

Ideally, the above example produces an error unless you use the override keyword. Albeit, I imagine that there would be a compiler flag to opt-out of override checking, where opting out is the same thing as override | define for all methods

bioball on 11 Nov 2020

@bioball yes, it's required for compatibility with a lot of existed code.

nin-jin on 11 Nov 2020

@sam-s4s Entity extends Base, of course. :-) I have fixed my message. virtual is about something else.

I'm still not sure what you mean by define... this is the definition of virtual in C#:

The virtual keyword is used to modify a method, property, indexer, or event declaration and allow for it to be overridden in a derived class.

Maybe you mean the opposite, where, instead of needing to mark the function as virtual in order to override, you can mark the function as define to then mean you have to use the override keyword to override it?

(why define? I have not seen that keyword in another language)

sam-s4s on 12 Nov 2020

I skimmed through this thead in a couple minutes, but I haven't seen anyone propose using override as a way to avoid duplicate specification of parameters and return values. For example:

class Animal {
    move(meters:number):void {
    }
}

class Snake extends Animal {
    override move(meters) {
    }
}

In the above example, move would have the same required return type (void) and meters would also have the same type, but specifying it wouldn't be necessary. The large company I work for is trying to migrate all our javascript to typescript, away from Closure compiler typing. However, while in Closure we can just use @override and all the types will be inferred from the superclass. This is quite useful in reducing the possibility for mismatch and reducing duplication. One could even imagine implementing this such that extension of the method with additional parameters is still possible, even while not specifying types for the parameters that are specified in the superclass. For example:

class Animal {
    move(meters:number):number {
    }
}

class Snake extends Animal {
    override move(meters, time:number) {
    }
}

The motivation for me coming here and writing a comment is that our company is now requiring that we specify all the types even for overridden methods, because typescript doesn't have this functionality (and we're in a long migration). Its quite annoying.

fresheneesz on 3 Dec 2020

FWIW, while it's easier to write, omitting parameter types (and other instances of cross-file type inference) hinders readability, since it requires someone unfamiliar with the code to dig around to find where the superclass is defined in order to know what type meters is (assuming you're reading it outside an IDE, which is quite common for unfamiliar projects where you don't have an IDE set up yet). And code is read much more often than it's written.

shicks on 3 Dec 2020

👍1

@shicks You could say that about literally any imported variable or class. Duplicating all the information you might need onto a single file defeats the purpose of abstraction and modularity. Forcing types to be duplicated violates the DRY principle.

fresheneesz on 3 Dec 2020

Typescript: Support override keyword on class methods

Example use

Example compile error conditions

IntelliSense

Proposed IntelliSense mechanism

Most helpful comment

All 210 comments

Failure to override

Failure to implement

Accidental override

Accidental `any`s

Readability

Editor experience

Non-problems

override / implements

override / `InterfaceName.`

`this.`

About overriding prototype with instance field

About `override`

About `New`

About overriding methods with fields

About interfaces

About new

About this.

Initial

Base class refactored

Case with `define` keyword

Related issues

Typescript: Support override keyword on class methods

Example use

Example compile error conditions

IntelliSense

Proposed IntelliSense mechanism

Most helpful comment

All 210 comments

Failure to override

Failure to implement

Accidental override

Accidental anys

Readability

Editor experience

Non-problems

override / implements

override / InterfaceName.

this.

About overriding prototype with instance field

About override

About New

About overriding methods with fields

About interfaces

About new

About this.

Initial

Base class refactored

Case with define keyword

Related issues

Accidental `any`s

override / `InterfaceName.`

`this.`

About `override`

About `New`

Case with `define` keyword