Typescript: Can't call 'super' when extending from 'any'

[andy-ms]

TypeScript Version: nightly (2.5.0-dev.20170707)

Code

declare const Super: any;
class C extends Super {
    constructor() {
        super();
    }
}

Expected behavior:

No error.

Actual behavior:

src/a.ts(4,3): error TS2346: Call target does not contain any signatures.

Ref: #14935, #14301

[vvkee]

How to solve

[andy-ms]

As a workaround, you could use class C extends (Super as { new(): any; }).

[sevenryze]

This form: class A extends ( React.component as { new(): any; } ) is not work. Is there any solution for it?

[andy-ms]

@sevenryze
You should be able to install @types/react, then import * as React from "react";. Then use React.Component instead of .component and it should be typed (and not need a cast).

[sevenryze]

@andy-ms yeh, I knew that way, that's works well.
But, for some reason, I want to just use the translate function of typescript(bypass the complex of typing system). So I expect a way to use plain JSX.
I see this issue is marked to bug and added to 2.8 milestone, that's good and I will wait for that time.
Anyway, thanks for your reply!

[andy-ms]

@sevenryze Actually, with "strict": false, I get no compile error from the following so long as I have react (not even @types/react) installed:

import * as React from "react";
class A extends (React.Component as { new(): any; }) {}

This is because without --noImplicitAny we allow you to import anything in your node_modules even if it lacks typings.

[sevenryze]

@andy-ms I try that again and confirm that what you told is works well. I think there maybe some config errors in my project and it's my mistake to not make sure of this problems.
Thanks for your answer, good job for TS team!