Typeorm: Persist new object without supplying full relation

[cameronpickham]

My entities:

@Entity('games')
class Game {
  @PrimaryColumn('uuid', { generated: true })
  id: string;
}

@Entity('runs')
class Run {
  @PrimaryColumn('uuid', { generated: true })
  id: string

  @RelationId((run: Run) => run.game)
  gameId: string;

  @ManyToOne(type => Game)
  @JoinColumn({ name: 'game_id' })
  game: Game;
}

How can I create and persist a new run, without supplying the full game object (I just have the ID)?
Right now I have to do something like this:

const run = new Run();
run.game = game;

repos.Runs.persist(run);

but I would prefer being able to do something like

const run = new Run();
run.gameId = gameId;

repos.Runs.persist(run);

Thanks.

[NoNameProvided]

You can write

const run = new Run();
run.game = { id: gameId };

repos.Runs.persist(run);

[cameronpickham]

If Game has additional properties, TypeScript complains because { id: gameId } is not the correct shape. Would you recommend doing something like run.game = { id: gameId } as Game or is there a different preference for this case?

[pleerock]

relation id is just to get your relation id, it won't work if you want to save through it. You have two options, first is what @NoNameProvided suggested (to prevent casting simply do: run.game = new Game(gameId), second is to define column together with relation:

@Entity('runs')
class Run {
  @PrimaryColumn('uuid', { generated: true })
  id: string

  @Column({ type: "int", nullable: true }) // both options must be set
  gameId: number;

  @ManyToOne(type => Game)
  @JoinColumn({ name: 'gameId' })
  game: Game;
}