Swagger-core: JSON wrapper object not mapped to proper OpenAPI model

[lwielek]

When a class is annotated with

@com.fasterxml.jackson.annotation.JsonTypeInfo(use = com.fasterxml.jackson.annotation.JsonTypeInfo.Id.NAME, include = com.fasterxml.jackson.annotation.JsonTypeInfo.As.WRAPPER_OBJECT)

it is being serialized as an object, rather than a simple string.
The OpenAPI model for such a class is represented as a simple value.

See example attached to issue #2862.

Serialized:

{"ExampleSubType":"VALUE1"}

Model:

Example:
  type: object
ExampleSubType:
  type: string
  allOf:
  - $ref: '#/components/schemas/Example'
  enum:
  - VALUE1
  - VALUE2

[jbraga]

I need this too :(
@lwielek, have you found a workaround?

[lwielek]

@jbraga
no, my workaround was not to use wrapper object annotations ...

[sakibulalam]

any progress on this issue?

[matejuh]

This is quite painful bug which blogs us to use specification generated from code. This test: https://github.com/swagger-api/swagger-core/blob/4f30e3eb594790bdbe4f4a12553a54e2f7d8c5cd/modules/swagger-core/src/test/java/io/swagger/v3/core/converting/ModelConverterTest.java#L130 is invalid.
It should be: employee.getProperties().get("employee").getProperties();

[dazraf]

Is there anyone reading this, or has development on swagger stopped?

[frantuma]

@dazraf there is indeed somebody reading, and nope, development has not stopped; as always contributions are more than welcome though..

That said a partial implementation has been implemented in #3921, available in latest snapshot and next release.