I want to open a link on a new tab. I shortened my code in below.
export default function () {
const classes = useStyles();
const [selectedIndex, setSelectedIndex] = React.useState(0);
const handleListItemClick = (
event: React.MouseEvent<HTMLDivElement, MouseEvent>,
index: number,
) => {
setSelectedIndex(index);
};
return (
<div className={classes.root}>
<Drawer
variant="permanent"
classes={{
paper: clsx(classes.drawerPaper, !open && classes.drawerPaperClose),
}}
open={open}
>
<div className={classes.toolbarIcon}>
<IconButton onClick={handleDrawerClose}>
<ChevronLeftIcon />
</IconButton>
</div>
<Divider />
<List>
<div>
<Link className={classes.link} to=''>
<ListItem
button
selected={selectedIndex === 0}
onClick={event => handleListItemClick(event, 0)}
>
<ListItemIcon>
<DashboardIcon />
</ListItemIcon>
<ListItemText primary="Panel" />
</ListItem>
</Link>
<Link className={classes.link} to='altkullanicilar'>
<ListItem
button
selected={selectedIndex === 1}
onClick={event => handleListItemClick(event, 1)}
>
<ListItemIcon>
<PeopleIcon />
</ListItemIcon>
<ListItemText primary="Alt Kullan谋c谋lar" />
</ListItem>
</Link>
</div>
</List>
</Drawer>
</div>
)
}
Just use an <a>
An anchor tag as suggested above will work and is really want you want if forwarding someone off of your site.
Though the accessibility feature surrounding this with a Link tag, is ctrl + click.
Would this be possible to implement, please?
yeah. looking for such solution also. Might need to pass states to the new opened Link as well. example,
<Link
to="photos/123"
state={{ fromFeed: true }}
newTab={true} // Example
/>
@jansila @loonfly you can implement it yourself with your own interface
e.g.
export const ExternalLink = ({ href, text }) => {
return <a href={href}>{text}</a>
}
Most helpful comment
Just use an
<a>