Version Used:
VS 16.8 Preview 6
Steps to Reproduce:
// File 1
public partial record R(int A, double B, float C);
// File 2
partial record R
{
public void Deconstruct(out int a, out double b) => (a, b) = (A, B);
}
R, and press F12 (or choose 'Find all references').Expected Behavior:
The name will be displayed well.
Actual Behavior:
Actually, two references is shown below:
public partial record R(int A, double B, float C)partial recordR.Screenshots:

I couldn't figure out the best area label to add to this issue. If you have write-permissions please help me learn by adding exactly one area label.
@allisonchou Did your PR #47960 handle this? (specifically the change of GetPartKind where SymbolDisplayPartKind.RecordName is returned); or this is another issue?
/cc @JoeRobich as well
This is fixed in master with Allison's PR

@JoeRobich Thank you. Should I close this issue?
Yup. Closing. Thanks for the report!
Most helpful comment
This is fixed in master with Allison's PR
