Python: Getting custom resources

[djamaile]

What is the feature and why do you need it:
Working with Istio I create new resources through the command line and not by code. The custom resource name is serviceentries. With kubectl you would do:

kubectl get serviceentries

Apparently it is not possible to get custom resources if they are not created by the python client itself. Don't if this is 100% sure, but I haven't seen a simple solution for this.

Describe the solution you'd like to see:
Would be cool if we can do something like this:

api.list_custom_resources_for_all_namespaces(resource="serviceentries")

[MoShitrit]

@djamaile you should be able to get your custom resources using the python client like this:

kubernetes.client.CustomObjectsApi().list_cluster_custom_object(group=<group>, version=<version>, plural=<plural>)

So for example if you have a custom resource named my-resources.example.com which serves version v1alpha1, you would run:

kubernetes.client.CustomObjectsApi().list_cluster_custom_object(group="example.com", version="v1alpha1", plural="my-resources")

Give that a try and let us know if that worked 😄

[djamaile]

Oh it worked! I asked this question on stackoverflow and someone told me that it is not possible. Here is the question: https://stackoverflow.com/questions/61594447/python-kubernetes-client-equivalent-of-kubectl-get-custom-resource/61594809#61594809

Maybe I worded it wrong? Either way you can give an answer there and i'll accept it or update the question with my own answer. Thanks!

[MoShitrit]

Thanks for pointing that out!
I'll share my answer there as well, feel free to mark it as the working solution 😄
Glad to help!!