Python-zeep: Simple WSDL query?

[grguthrie]

I want to do a simple thing;
what is the python version of the command line:
user> python -mzeep http://www.soapclient.com/xml/soapresponder.wsdl

Try the Demo web service

wsdl = 'http://www.soapclient.com/xml/soapresponder.wsdl'
client = zeep.Client(wsdl=wsdl)
print(client.service.???())

And is this a standard SOAP service for any server to query its WSDL?

[mvantellingen]

Sorry, I have no idea what you mean

[grguthrie]

Thanks. I had only meant - is there a way programmatically (e.g. in Python) to list the wsdl in the same manner that the example command-line does.

[vstoykov]

@grguthrie what I found is that you can do the following:

wsdl = 'http://www.soapclient.com/xml/soapresponder.wsdl'
client = zeep.Client(wsdl=wsdl)
client.wsdl.dump()

This will print the same info that is printed when you execute:

python -mzeep http://www.soapclient.com/xml/soapresponder.wsdl

You can reed the source to see how different parts of the information are taken
https://github.com/mvantellingen/python-zeep/blob/1668fe1b0a75a161b88421a52ad45a3e07db8aee/src/zeep/wsdl/wsdl.py#L73-L115

[grguthrie]

Thank you.

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| Dr. Gregory Guthrie |

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From: Venelin Stoykov [mailto:[email protected]]
Sent: Wednesday, January 11, 2017 2:03 AM
To: mvantellingen/python-zeep [e-mail]
Cc: Gregory Guthrie [e-mail]; Mention [e-mail]
Subject: Re: [mvantellingen/python-zeep] Simple WSDL query? (#297)

@grguthriehttps://github.com/grguthrie what I found is that you can do the following:

wsdl = 'http://www.soapclient.com/xml/soapresponder.wsdl'

client = zeep.Client(wsdl=wsdl)

client.wsdl.dump()

This will print the same info that is printed when you execute:

python -mzeep http://www.soapclient.com/xml/soapresponder.wsdl

You can reed the source to see how different parts of the information are taken
https://github.com/mvantellingen/python-zeep/blob/1668fe1b0a75a161b88421a52ad45a3e07db8aee/src/zeep/wsdl/wsdl.py#L73-L115

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