I am sorry, but I think the variance of Weibull distribution shown in https://docs.pymc.io/api/distributions/continuous.html#pymc3.distributions.continuous.Weibull is simply wrong. It does not equal to \beta^2\Gamma(1+2/\alpha-\mu^2), but \beta^2(\Gamma(1+2/\alpha)-\mu^2/\beta^2). At least, the Wikipedia page on Weibull distirubution confirms my guess
well, I think you are right. Let me to make a pr to fix it.
@chang111 Because it is on the same page, you could also remove an unnessary closing bracket in the denominator of the p.d.f. of Wald distribution (just after \pi)
Good advice!
Thanks!
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well, I think you are right. Let me to make a pr to fix it.