Instagram-php-scraper: Video media not returning an URL

[eelcol]

Videos are not returning an URL to the video anymore. See example below.

[type:protected] => video
[link:protected] => https://www.instagram.com/p/BbVOUCvHSnY
[imageLowResolutionUrl:protected] => https://scontent.cdninstagram.com/t/s320x320/23498942_1896518027320877_1615031175015825408_n.jpg
[imageThumbnailUrl:protected] => https://scontent.cdninstagram.com/t/s150x150/23498942_1896518027320877_1615031175015825408_n.jpg
[imageStandardResolutionUrl:protected] => https://scontent.cdninstagram.com/t/s640x640/23498942_1896518027320877_1615031175015825408_n.jpg
[imageHighResolutionUrl:protected] => https://scontent.cdninstagram.com/t/23498942_1896518027320877_1615031175015825408_n.jpg
[videoLowResolutionUrl:protected] =>
[videoStandardResolutionUrl:protected] =>
[videoLowBandwidthUrl:protected] =>

[adgray]

It looks like the Instagram web-video player downloads video and audio tracks separately in 2-second chunks, and the track URLs aren't published in graphql responses. You can fetch the HTML player view for a video item from https://www.instagram.com/p/{{shortcode}} and you can scrape this for the meta tag with property="og:video" content="{{video_url}}" to get the URL for the full video.

[pedropamn]

I did:

$midias = $instagram->getMedias($username,10);

            for ($i=0; $i<count($midias); $i++) {               
                if($midias[$i]->getType() == 'video'){
                    $link = $midias[$i]->getLink();
                    $json_media_by_url = $instagram->getMediaByUrl($link);
                    $video_url = $json_media_by_url['videoStandardResolutionUrl'];                  
                }

[afifmakarim]

this is works for me 👍

$media = $instagram->getMediaByUrl('https://www.instagram.com/p/BGuQBXrDH_b/');             
                if($media->getType() == 'video'){
                    $link = $media->getLink();
                    $json_media_by_url = $instagram->getMediaByUrl($link);
                    $video_url = $json_media_by_url['videoStandardResolutionUrl'];                  
                }
                echo $video_url;

[ariefhyda]

I did:

$midias = $instagram->getMedias($username,10);

          for ($i=0; $i<count($midias); $i++) {               
              if($midias[$i]->getType() == 'video'){
                  $link = $midias[$i]->getLink();
                  $json_media_by_url = $instagram->getMediaByUrl($link);
                  $video_url = $json_media_by_url['videoStandardResolutionUrl'];                  
              }

greeattt!!!

[stale[bot]]

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