You can get the ---> as a combination of -- and ->; would be nice if there was a ligature for it and if it was somehow different from the -> ligature.
nesteruk
All 5 comments
Can you provide an example of how this could've happen?
tonsky
on 2 Aug 2016
Let's say you have a class Foo implementing operator-- that returns a Bar& and then you have a Bar that has operator ->. Thus, you can write foo--->whatever();.
nesteruk
on 2 Aug 2016
@nesteruk Those are two different operations, and I don't think it makes any sense to combine them. After all, the whole point of ligatures is to convert two-character sequences that have a single meaning to a single token that our brain has to process. If foo--->whatever() was converted to one long arrow, your brain would have to actively *disassemble" it into the -- and -> operators, which is counter-productive to the goal of ligatures.
JonathonReinhart
on 11 Aug 2016
Sorry for my two cents, but I honestly think this is really a silly idea to want it for c++. I mean I could understand if you want it for another programming language that has the ---> token, but not for c++.
krux02
on 13 Aug 2016
Yeah, if that鈥檚 two different operations we don鈥檛 want to have them as a single ligature. It鈥檒l be against the font goals
tonsky
on 17 Sep 2016
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Most helpful comment
@nesteruk Those are two different operations, and I don't think it makes any sense to combine them. After all, the whole point of ligatures is to convert two-character sequences that have a single meaning to a single token that our brain has to process. If
foo--->whatever()was converted to one long arrow, your brain would have to actively *disassemble" it into the--and->operators, which is counter-productive to the goal of ligatures.