Chromedp: help, how to get all subnode in a element

[seanchann]

I want to get all subnode in a element. use above code

func search(nodes *[]*cdptypes.Node) cdp.Tasks {

    return cdp.Tasks{
        cdp.Navigate(`https://www.****.com`),
        cdp.Sleep(2 * time.Second),
        cdp.Nodes(`#lt-center > #MOP > #odds-tbl-containers > #sc1 > #s1`, nodes),
        cdp.ActionFunc(func(context.Context, cdptypes.FrameHandler) error {
            return nil
        }),
    }
}

the nodes only have one element, the node.ChildNodeCount = 30 but, not have any sub node in node.Children

[rnd]

You just need to define it in the selectors.
For example, look at the selector i write bellow. It will tell chromedp to fetch all a elements which a child of ul[class="list-unstyled"] > li

var nodes []*cdptypes.Node
t := chromedp.Tasks{
    chromedp.Navigate(`https://godoc.org`),
    chromedp.Sleep(time.Second * 2),
    chromedp.Nodes(`ul[class="list-unstyled"] > li > a`, &nodes, chromedp.ByQueryAll),
}

err = c.Run(ctx, t)
if err != nil {
    log.Fatal(err)
}

for _, n := range nodes {
    fmt.Printf("got package: %s \n", n.AttributeValue("href"))
}

Just be creative with your selectors.

[seanchann]

@ranch thanks!

[patanasov]

How can we do this with XPath selector?
We have byQuery and byQueryAll, there is also bySearch (which is working with XPath) but there is no bySearchAll.