Appium: Question: Separating press and release action for iOS

[kkb912002]

touch_action = TouchAction(driver)
touch_action.press(x=10, y=10).perform() # line 2
...(pressing now...)
touch_action.release().perform() # line 4

This code works fine on Android(UIAutomator2).
But on iOS(XCUITest), released right after line 2. And error occurred on line 4.
Is it not possible on iOS?

Of course

touch_action.press(x=10, y=10).wait(1000).release().perform()

works fine both Android and iOS.

Thanks.

[mykola-mokhnach]

Is it not possible on iOS?

No, such gesture won't work on iOS, because this is the way XCTest "understands" gestures.

See
https://github.com/appium/appium/blob/master/docs/en/writing-running-appium/ios/actions.md
https://github.com/appium/appium/tree/master/docs/en/writing-running-appium/android/actions.md
for more details.

Please use Appium forum to ask questions