Amplify-cli: Amplify function specify source location

[set321go]

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* Which Category is your question related to? *
Amplify Cli functions
* What AWS Services are you utilizing? *
Appysync, dynamo, lambda
* Provide additional details e.g. code snippets *
I couldn't find my answer in the docs for amplify or in the more general aws docs for functions.

I have an amplify project with a function that I originally created with all the code in src/ but I have now added webpack to package up the function code which outputs to src/bin. How do I tell amplify to target that specific directory to create the zip that it puts in the dist/ dir?
i.e I would like to zip the output of webpack not the src.

It looks like it runs my script "amplify:my-function": "npm run lint && npm run webpack"

I tried changing the lambda function aws:asset:path in the medatadate section in cloud formation template but I don't think its used here

[UnleashedMind]

@set321go
What's the value of the aws:asset:path that you put in your cloudformation template?

[set321go]

"aws:asset:path": "./src" I tried changing it to ./src/bin but after building the function dist/lastest-build.zip still includes all of ./src

[kaustavghosh06]

@set321go The build process happens out here - https://github.com/aws-amplify/amplify-cli/blob/master/packages/amplify-provider-awscloudformation/lib/build-resources.js#L21 and as you can see this is hard-coded to the src/ directory right now..so I would treat this request as an enhancement.

[thomasklein-winemaker]

Hi! Any news on this one? Or any other suggestion on how to effectively minify the code without any "hacks" around the amplify conventions?

References

• serverless-webpack-plugin
• Article on improved invoke time warm and cold start

[bstriner]

Should work if you put the code somewhere else and webpack to src?