Algo_ds_101: Find cycle in a Linked List

Created on 5 Oct 2020  路  19Comments  路  Source: ahampriyanshu/algo_ds_101

Submission Title
Find cycle in a Linked List

Submission Type
Data Structure

Submission Description
Given a linked list, check if the linked list has loop or not

Submission Directory
Main_Folder => Data_Structures => Linked_List => Singly_Linked_List => DetectCycle.cpp

Contributors

  • [x] C++ -
  • [x] C -
  • [x] Python -
  • [x] Java -
  • [ ] JavaScript -
  • [ ] TypeScript -
  • [ ] Golang -
  • [ ] Ruby -
  • [ ] php -
  • [ ] Swift -
  • [ ] C# -
C# Hacktoberfest New Submssion TypeScript first timer good first issue javascript php ruby scala swift

All 19 comments

馃憢 @Shreyash0713

Thanks for opening your first issue here! Be sure to follow the issue template! |+ Regards @ahampriyanshu :v:

Can I work on this issue, please review.

Can I code this in cpp

馃憢 @Shreyash0713

Thanks for opening your first issue here! Be sure to follow the issue template! |+ Regards @ahampriyanshu :v:

Hello, can I work on this issue(C++)?

Can i implement this using C++?

Can I contribute in Java?

Can I implement this in Python?

Hi @garimamishraa
Please opt a different language/issue :v:

Can I write in C#? Please assign it to me.

Hi, it seems that the C++ code has already been submitted and merged, can I submit the solution in Golang?
Edit: I am getting this error: https://github.com/actions/first-interaction/issues/10 which seems to be because I don't have permission to the repository, can you please let me know what I should do to resolve the same(I have not been added as a contributor, not sure if that is an issue).

Hey, I would like to submit it with TypeScript

hey can i do this in javascript??

I would like to work on this in C++. Can you please assign it to me?

I'd like to do it with Ruby 馃檶

I would like to do it in swift using tortoise method:-)

can you please assign it to me?

Hey @Shreyash0713 ., i would like to work on this issue in Golang. Can you assign this to me..

thanks everyone :v:

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